Equilibrium
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What mass of 95% pure CaCO3 will be require neutralise 50 mL of 0.5M HCl solution according to the following reaction?
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l) [Calculate upto second place of decimal point]
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What mass of 95% pure CaCO3 will be require neutralise 50 mL of 0.5M HCl solution according to the following reaction?
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l) [Calculate upto second place of decimal point]
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Moles of HCl = (50 / 1000) × 0.5 = 0.025 moles
So, moles of CaCO? used = 0.025 / 2 = 0.0125 moles = 1.25 g
95% (Total mass of CaCO? ) = 1.25 g
Total mass of CaCO? = 1.25 / 0.95 = 1.32 g
Upvote 
The pH of the solution containing 50 mL each of 0.10M sodium acetate and 0.01M acetic acid is:
[Given pKa of CH3COOH = 4.57 ]
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The pH of the solution containing 50 mL each of 0.10M sodium acetate and 0.01M acetic acid is:
[Given pKa of CH3COOH = 4.57 ]
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pH = pK? + log ( [CH? COONa] / [CH? COOH])
pH = 4.57 + log (0.1 / 0.01) = 5.57
Upvote Sulphurous acid (H₂SO₃) has Ka₁ = 1.7 × 10⁻² and Ka₂ = 6.4 × 10⁻⁸ . The pH of 0.588 M H₂SO₃ is __________.
Sulphurous acid (H₂SO₃) has Ka₁ = 1.7 × 10⁻² and Ka₂ = 6.4 × 10⁻⁸ . The pH of 0.588 M H₂SO₃ is __________.
Sucralose: Artificial sweetener
Glyceryl ester of stearic acid: The document incorrectly identifies this as "Sodium stearate which is synthetic detergent". Sodium stearate is a soap, not a synthetic detergent.
Sodium benzoate: Food preservative
Bithionol: Antiseptic
Upvote For the coagulation of a negative sol, the species below, that has the highest flocculating power is:
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For the coagulation of a negative sol, the species below, that has the highest flocculating power is:
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For the coagulation of a negative sol, the species Ba²? has the highest flocculating power (referring to the Hardy-Schulze rule, where higher charge leads to greater coagulation power).
Upvote 0.01 moles of a weak acid HA (Ka = 2.0 ×10-6) is dissolved in 1.0 L of 0.1 M HCl solution. The degree of dissociation of HA is _______ ×10-5. (Round off to the nearest integer).
[Neglect volume change on adding HA. Assume degree of dissociation <<1]
0.01 moles of a weak acid HA (Ka = 2.0 ×10-6) is dissolved in 1.0 L of 0.1 M HCl solution. The degree of dissociation of HA is _______ ×10-5. (Round off to the nearest integer).
[Neglect volume change on adding HA. Assume degree of dissociation <<1]
For the weak acid HA in the presence of strong acid HCl:
Ka = [ (Cα + 0.1) × Cα] / [C (1-α)] ≈ (0.1 × 10? ²α) / 10? ² = 0.1α
Given Ka = 2 × 10?
2 × 10? = 10? ¹ × α
α = 2 × 10?
Ans = 2
Upvote Consider the following reaction:
N₂O₄ ⇌ 2NO₂(g); ∆H° = +58 kJ
For each of the following cases (a, b) the direction in which the equilibrium shifts is:
Consider the following reaction:
N₂O₄ ⇌ 2NO₂(g); ∆H° = +58 kJ
For each of the following cases (a, b) the direction in which the equilibrium shifts is:
In endothermic reaction formation of reactants is favoured upon decrease in temperature. Addition of inert gas at constant volume and temperature has no effect on equilibrium.
Upvote 