Hydrocarbons
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5 months agoContributor-Level 10
(i) The two substituents in the benzene ring are present at p-positions. Therefore, the sequence of reactions should be such that first an o, p-directing group, i.e., Br atom should be introduced in the benzene ring and this should be followed by nitration. Thus,
New answer posted
5 months ago
Contributor-Level 10
planar. It does contain six n-electrons but the system is not fully conjugated since all the six n-electrons do not form a single cyclic electron cloud which surrounds all the atoms of the ring. Therefore, it is not an aromatic compound.
Cyclo-octatetraene is not planar but is tub shaped. It is, therefore, a non-planar system
New answer posted
5 months agoContributor-Level 10
The necessary conditions for a molecule to be aromatic are:
- It should have a single cyclic cloud of delocalised n-electrons above and below the plane of the molecule.
- It should be planar. This is because complete delocalization of n-electrons is possible only if the ring is planar to allow cyclic overlap of p-orbitals.
- It should contain Huckel number of electrons, i.e., (4n + 2) n-electrons where n = 0, 1, 2, 3 etc.
A molecule which does not satisfy any one or more of the above conditions is said to be non-aromatic.
New answer posted
5 months agoContributor-Level 10
Benzene is a resonance hybrid of two canonical forms. In the resonance hybrid, all the six pi electrons are completely delocalized. This results in resonance stabilization.
New answer posted
5 months agoContributor-Level 10
The structures of cis- and trans-isomer of hex-2-ene are:
The boiling point of a molecule depends upon dipole-dipole interactions. Since cis-isomer has higher dipole moment, therefore, it has higher boiling point.
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5 months agoContributor-Level 10
A combustion reaction is a reaction in which a substance reacts with oxygen gas, there is a formation of carbon dioxide, water with the evolution of light and heat.
(i) 2C4H10 (g) +13 O2 (g)?8CO2 (g)+10H2O (g) + Heat
(ii) 2C5H10 (g) +15 O2 (g)?10CO2 (g)+10H2O (g) + Heat
(iii) 2C6H10 (g) +17 O2 (g)?12CO2 (g)+10H2O (g) + Heat
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5 months agoContributor-Level 10
The ozonolysis of 4-Ethylhex-3-ene gives propanal and pentan-3-one.
The structural formula of the alkene (4-Ethylhex-3-ene) is as shown.
New answer posted
5 months agoContributor-Level 10
(i) An aldehyde with molar mass of 44 u is ethanal, CH3CH=0
(ii) Write two moles of ethanal side by side with their oxygen atoms pointing towards each other.
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5 months agoContributor-Level 10
Step 1. Write the structure of the products side by side with their oxygen atoms pointing towards each other.
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5 months agoTaking an Exam? Selecting a College?
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