Hydrocarbons

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The electron donating group increases the reactivity in electrophilic substitution reaction whereas the electron withdrawing group decreases the reactivity in electrophilic substitution.

Thus, the order of reactivity

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The benzene here would undergo Friedel-Crafts alkylation reaction where carbocation is formed as an intermediate, thus secondary carbocation is formed as an intermediate due to its greater stability than that of the primary carbocation.

The final product obtained is 

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The rate-determining step involved in the reaction is 

CH3-CH=CH2 + HX → CH3-CH+-CH3 + X-

So the rate-determining step depends on the bond energy of HX i.e. higher the bond energy lesser would be reactivity.

Thus the order of reactivity of these halogen acids is

HI>HBr>HCl

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The rotation around C-C single bond is possible but it is not completely free due to the torsional strain which is about 1-20 KJ mol-1.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Yes, it will execute geometrical isomerism as the product formed can be either cis-2-butene or trans-2-butene.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

If arenes would undergo electrophilic addition reaction then they would lose their aromaticity which would lead to comparatively less stability. However, alkenes undergo electrophilic addition reaction via carbocation intermediate.

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Payal Gupta

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This is a long answer type question as classified in NCERT Exemplar

The bond energy of HCl is higher than that of HBr thus it is not cleaved by free radical mechanism to exhibit peroxide effect. However in case of HI the bond energy is so low that the iodine radical forms readily and after formation it combines to form an iodine molecule.

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

The structure of A is

The reaction involved are as follows:

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