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Introduction to Three Dimensional Geometry

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2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

The locus of a point for which $y = 0, z = 0$ is

(a) Equation of $x$ -axis

(b) Equation of $y$ -axis

(c) Equation of $z$ -axis

(d) None of these

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New answer posted

2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

A plane is parallel to yz-plane so it is perpendicular to:

(a) x -axis

(b) y-axis

(c) z-axis

(d) None of these

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} A n y p l a n e p a r a l l e l t o y z - p l a n e i s p e r p e n d i c u l a r t o x - a x i s . \\ H e n c e, t h e c o r r e c t o p t i o n i s (a) . \end{array}$

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New question posted

2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

A plane is parallel to yz-plane so it is perpendicular to:

(a) x -axis

(b) y -axis

(c) z -axis

(d) None of these

0 Follower 1 View

New question posted

2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

A plane is parallel to $y z$ -plane so it is perpendicular to:

(a) $x$ -axis

(b) $y$ -axis

(c) $z$ -axis

(d) None of these

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New answer posted

2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

The point $(2, 3, 4)$ lies in the

(a) First octant

(b) Seventh octant

(c) Second octant

(d) Eighth octant

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} T h e point (- 2, - 3, - 4) l i e s i n s e v e n t h octant . \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

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New answer posted

2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

Equation of $y$ -axis is considered as

(a) $x = 0, y = 0$

(b) $y = 0, z = 0$

(c)

(d) None of these

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} O n y - a x i s, x = 0 a n d z = 0 \\ H e n c e, t h e c o r r e c t o p t i o n i s (c) . \end{array}$

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New answer posted

2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

$x$ -axis is the intersection of two planes

(a) $x y$ and $x z$

(b) $y z$ and $z x$

(c) $x y$ and $y z$

(d) None of these

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} W e k n o w t h a t o n t h e x y a n d x z p l a n e s, t h e l i n e o f intersection i s x a x i s . \\ H e n c e, t h e c o r r e c t o p t i o n i s (a) . \end{array}$

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2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

If the distance between the points $(a, 0, 1)$ and $(0, 1, 2)$ is $\sqrt[]{27}$ , then the value of $a$ is

(a) 5

(b) $\pm 5$

(c) –5

(d) None of these

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} L e t t h e g i v e n points b e A (a, 0, 1) a n d B (0, 1, 2) \\ ∴ A B = \sqrt[]{{(a - 0)}^{2} + {(0 - 1)}^{2} + {(1 - 2)}^{2}} \\ \sqrt[]{27} = \sqrt[]{a^{2} + 1 + 1} \\ S q u a r i n g b o t h s i d e s, w e g e t \\ 27 = a^{2} + 2 \Rightarrow a^{2} = 25 ∴ a = \pm 5 \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

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New answer posted

2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

Distance of the point $(3, 4, 5)$ from the origin $(0, 0, 0)$ is

(a) $\sqrt[]{50}$

(b) 3

(c) 4

(d) 5

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} G i v e n points A (3, 4, 5) a n d t h e g i v e n O (0, 0, 0) \\ ∴ O A = \sqrt[]{{(3 - 0)}^{2} + {(4 - 0)}^{2} + {(5 - 0)}^{2}} = \sqrt[]{9 + 16 + 25} = \sqrt[]{50} \\ H e n c e, t h e c o r r e c t o p t i o n i s (a) . \end{array}$

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New answer posted

2 months ago

Introduction to Three Dimensional Geometry Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

What is the length of the foot of the perpendicular drawn from the point $P (3, 4, 5)$ on the $y$ -axis?

(a) $\sqrt[]{41}$

(b) $\sqrt[]{34}$

(c) 5

(d) None of these

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} O n y - a x i s, x = 0 a n d z = 0 g i v e n point i s P (3, 4, 5) \\ ∴ T h e point A i s (0, 4, 0) \\ ∴ P A = \sqrt[]{{(0 - 3)}^{2} + {(4 - 4)}^{2} + {(0 - 5)}^{2}} = \sqrt[]{9 + 0 + 25} = \sqrt[]{34} \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

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