JEE Main
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New answer posted
7 years ago
Contributor-Level 9
His percentile is too low to get admission in any good engineering college with a specified branch, I would suggest you to ask him to prepare for the exam again that will be held in April and best of two scores will be counted, so it's the best chance for him to improve his score.
New answer posted
7 years ago
Contributor-Level 9
Wait for the final rank, before that we cannot predict that you are eligible or not. The final AIR will come in April 2019 and the best of 2 JEE Mains scores will be taken into account.
New answer posted
7 years ago
Scholar-Level 18
You have got a very decent score in JEE Mains. It is expected that the cut-off would be between percentile figures of 75 and 80 and hence with this you will definitely become eligible to appear for JEE Advanced and also eligible to seek admission in NIT, but whether you will get admission in NIT or not will depend on how many with better percentile than you seek admission for the course and the NIT that you desire. I am attaching a link that will predict college for you once you input your percentile. I would, however, like to advise you that you must appear for the exam again in the month of April for improving your pe
New answer posted
7 years agoGuide-Level 13
Details:
https://www.shiksha.com/b-tech/articles/how-to-calculate-jee-main-rank-from-percentile-blogId-19953
New answer posted
7 years agoGuide-Level 13
Details:
https://www.shiksha.com/b-tech/articles/how-to-calculate-jee-main-rank-from-percentile-blogId-19953
New answer posted
7 years agoGuide-Level 13
Details:
https://www.shiksha.com/b-tech/articles/how-to-calculate-jee-main-rank-from-percentile-blogId-19953
New answer posted
7 years agoContributor-Level 10
https://www.shiksha.com/b-tech/resources/jee-main-rank-predictor
New answer posted
7 years ago
Scholar-Level 18
For information about cutoffs of JEE Mains 2018 & previous years, I am attaching another link. https://www-shiksha-com.cdn.ampproject.org/v/s/www.shiksha.com/b-tech/amp/jee-main-exam-cutoff?amp_js_v=a2&_gsa=1&usqp=mq331AQCCAE=#referrer=https://www.google.com&_tf=From %1$s&share=https://www.shiksha.com/b-tech/jee-mai
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