JEE Main

Admission to NIT Patna (CSE) requires closing ranks between 10,529 to 13,706 in JoSAA for general candidates. Since your rank is much higher than that, CSE at any NIT is not attainable in the general category.

General cutoff trends for IIITs (CSE) range from ~15,000–40,000 rank? requiring 97–98+ percentile. So IIITs are also out of reach for CSE with your current rank

No, with an 83.5 percentile, getting Computer Science & Engineering (CSE) at any NIT is almost impossible.

CSE cutoffs at even lower-tier NITs typically require 97–99+ percentile, and top-tier ones demand 99.2–99.5 percentile

With a JEE Main percentile of 63.5, your Common Rank List (CRL) rank is likely around 3.2 to 3.4 lakh. At this rank,  getting admission into any NIT is highly unlikely, especially in the open (General) category.

With a JEE Main rank of around 2,57,000,  getting admission to HBTU Kanpur (Harcourt Butler Technical University) for B.Tech programs is extremely difficult, especially for core branches like CSE, IT, or AI.

With 83.2685530 percentile in JEE Main, your chances for B.Tech in Computer Science (CSE) at top NITs, IIITs, or GFTIs are very low, especially for General category. However, you can still get admission into good private colleges,  state government colleges, and some lower-ranked GFTIs, depending on your category, home state, and counseling choice.

A U-shaped magnet is another type of bar magnet. This is known as a horseshoe magnet since its shapes resembles the object called horseshoe. The two ends of this U-shaped magnet are its magnetic poles. Configration of these magnetic poles creates a concentrated magnetic field. This concentrated magnetic field makes it much more stronger than a simple and straight bar magnet.