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New answer posted

4 months ago

0 Follower 1 View

P
Pallavi Pathak

Contributor-Level 10

The EM wave speed in a vacuum is determined by the permeability and permittivity of free space. It is given by the formula:

 c = 1 ? 0 ? 0

The constant value is around  3 * 10 8  m/s.

This speed forms the basis for many scientific and technological applications. It is a fundamental physical constant.

New answer posted

4 months ago

0 Follower 2 Views

P
Pallavi Pathak

Contributor-Level 10

The electric field (E) and magnetic field (B) in an electromagnetic wave are always perpendicular to each other and to the direction of wave propagation. The EM waves are transverse in nature. When the EM waves are moving along the X-axis, then along the y-axis, the electric field may oscillate and the magnetic field along the z-axis.

New answer posted

4 months ago

0 Follower 7 Views

P
Pallavi Pathak

Contributor-Level 10

Maxwell introduced the displacement current which ensures that when the conduction current is absent, the current continues in the circuits, such as in the capacitors. The displacement current plays a significant role in the derivation of electromagnetic waves. It shows that an electric field that is changing can produce a magnetic field. In free space, it enables wave propagation.

New answer posted

4 months ago

0 Follower 10 Views

R
Rupesh Katariya

Contributor-Level 10

If you're interested in B.Tech CSE, go for a college with good placements, strong faculty, and active coding culture. Some great options are VIT, SRM, MIT-WPU, and Chandigarh University. These colleges have a strong CSE community, support system, and good campus life—perfect for growing in the tech field.

New answer posted

4 months ago

0 Follower 5 Views

R
Rupesh Katariya

Contributor-Level 10

Hello! With a JEE rank around 8.2 lakh, it might be tough to get into top-tier government colleges, but don't worry—you still have good private college options for B.Tech in CSE with decent placements. You can consider:

  • Lovely Professional University (LPU)

  • Chandigarh University

  • Amity University (Noida)

  • Parul University (Vadodara)

  • MIT ADT (Pune)

These colleges offer CSE course  with  a good campus placements if you work on your skills (DSA, web development etc. ).

New answer posted

4 months ago

0 Follower 1 View

C
Chanchal Patra

Contributor-Level 7

If you don't meet the official cutoff, which is the minimum required to be on the merit list and be eligible for registration tests, you can't take part in the NCHMCT MSc JEE 2025 counselling. To participate you need to fulfil following criteria:

  • Cutoff Point:  The lowest qualifying score or rank required for admission eligibility is known as the NCHMCT JEE cutoff.  Counselling is only available to people who reach or exceed this threshold. Those who pass the cutoff are added to the merit list, where they can register, fill out forms, and take part in seat distribution.
  • No Counselling If There Is No Cutoff:  The portal wil
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