JEE
Get insights from 16.8k questions on JEE, answered by students, alumni, and experts. You may also ask and answer any question you like about JEE
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
4 months agoContributor-Level 10
The EM wave speed in a vacuum is determined by the permeability and permittivity of free space. It is given by the formula:
The constant value is around
This speed forms the basis for many scientific and technological applications. It is a fundamental physical constant.
New answer posted
4 months agoContributor-Level 10
The electric field (E) and magnetic field (B) in an electromagnetic wave are always perpendicular to each other and to the direction of wave propagation. The EM waves are transverse in nature. When the EM waves are moving along the X-axis, then along the y-axis, the electric field may oscillate and the magnetic field along the z-axis.
New answer posted
4 months agoContributor-Level 10
Maxwell introduced the displacement current which ensures that when the conduction current is absent, the current continues in the circuits, such as in the capacitors. The displacement current plays a significant role in the derivation of electromagnetic waves. It shows that an electric field that is changing can produce a magnetic field. In free space, it enables wave propagation.
New answer posted
4 months agoContributor-Level 10
If you're interested in B.Tech CSE, go for a college with good placements, strong faculty, and active coding culture. Some great options are VIT, SRM, MIT-WPU, and Chandigarh University. These colleges have a strong CSE community, support system, and good campus life—perfect for growing in the tech field.
New answer posted
4 months agoContributor-Level 10
Hello! With a JEE rank around 8.2 lakh, it might be tough to get into top-tier government colleges, but don't worry—you still have good private college options for B.Tech in CSE with decent placements. You can consider:
Lovely Professional University (LPU)
Chandigarh University
Amity University (Noida)
Parul University (Vadodara)
MIT ADT (Pune)
These colleges offer CSE course with a good campus placements if you work on your skills (DSA, web development etc. ).
New answer posted
4 months agoContributor-Level 7
If you don't meet the official cutoff, which is the minimum required to be on the merit list and be eligible for registration tests, you can't take part in the NCHMCT MSc JEE 2025 counselling. To participate you need to fulfil following criteria:
- Cutoff Point: The lowest qualifying score or rank required for admission eligibility is known as the NCHMCT JEE cutoff. Counselling is only available to people who reach or exceed this threshold. Those who pass the cutoff are added to the merit list, where they can register, fill out forms, and take part in seat distribution.
- No Counselling If There Is No Cutoff: The portal wil
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers