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New answer posted
8 months agoContributor-Level 10
……… (i)
……… (ii)
……… (iii)
Centre of the circle given by solving (i) & (ii)
Again is tangent to the circle.
New answer posted
8 months agoContributor-Level 10
⇒ 1 < (a 3)2 + (b + 2)2 < 16
in equivalent to 1 < 2 + β2
< 16
Total 40 such points are possible
New answer posted
8 months agoContributor-Level 10
gen term = 
For constant term
36 – 3r – rk = 0
for r = 1, 2, 4
12Cr212-r>28
Possible values of k = 3, 1
New answer posted
8 months agoContributor-Level 10
1 < a1 < a2 ……18 < 77
77 = 1 + (20 – 1) . d If n numbers are in A.P.
76 = 19 * d ⇒ d = 4
⇒ a1 = 5
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