Maths

Get insights from 6.5k questions on Maths, answered by students, alumni, and experts. You may also ask and answer any question you like about Maths

Follow Ask Question
6.5k

Questions

0

Discussions

18

Active Users

0

Followers

New answer posted

a year ago

0 Follower 15 Views

A
alok kumar singh

Contributor-Level 10

 x2a2+y2b2=1(ab);2b2a=10⇒b2=5a

Now, ?(t)=512+t-t2=812-t-122
?(t)max=812=23=e⇒e2=1-b2a2=49

⇒a2=81 (From (i) and (ii)

So, a2+b2=81+45=126

New answer posted

a year ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

 f (2)=8, f' (2)=5, f' (x)≥1, f'' (x)≥4, ∀x∈ (1,6)

Using LMVT

f'' (x)=f' (5)-f' (2)5-2≥4⇒f' (5)≥17

f' (x)=f (5)-f (2)5-2≥1⇒f (5)≥11

Therefore f' (5)+f (5)≥28

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

∫03? g (x)-f (x)=∫03? ||x-2|-2|dx-∫03? |x-2|dx

=12*2*2+1+12*1*1-12*2*2+12*1*1

=2+1+12-2+12=1

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

 x2-3x+p=0

α, β, γ, δ in G.P.

α+αr=3

x2-6x+q=0

αr2+αr3=6

(2)÷ (1)⇒r2=2

So,  2q+p2q-p=2r5+r2r5-r=2r4+12r4-1=97

New answer posted

a year ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

y+2x=11+77 ……… (i)

2y+x=211+67 ……… (ii)

⇒x+y=11+1337 ……… (iii)

Centre of the circle given by solving (i) & (ii)

as (873, 11+573)

Again 11y−3x=5773 is tangent to the circle.

∴ r = | 1 1 ( 1 1 + 5 7 3 ) − 8 7 − 5 7 7 3 1 1 + 9 | = | 1 1 − 8 7 2 0 |

∴ ( 5 h − 8 k ) 2 + 5 r 2 = 8 1 6

New answer posted

a year ago

0 Follower 15 Views

P
Payal Gupta

Contributor-Level 10

1 < | z − 3 + 2 i | < 4

z = a + i b a , b ∈ I              

⇒ 1 < (a 3)2 + (b + 2)2 < 16

in equivalent to 1 < 2 + β2 < 16  α = a − 3 ∈ l               

( ± 2 , 0 ) ( ± 3 , 0 ) , ( 0 , ± 2 ) ( 0 , ± 3 )             β = b + 2 ∈ l

Total 40 such points are possible

New answer posted

a year ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

(2x3+3xk)12

gen term =

=12Cr212−r.3r.x36−3r−rk

For constant term

36 – 3r – rk = 0

⇒k=36−3rr

for r = 1, 2, 4

12Cr212-r>28

Possible values of k = 3, 1

New answer posted

a year ago

0 Follower 17 Views

P
Payal Gupta

Contributor-Level 10

1 < a1 < a2 ……18 < 77

77 = 1 + (20 – 1) . d If n numbers are in A.P.

76 = 19 * d ⇒ d = 4

⇒ a1 = 5

∴ a 1 + a 2 + . . . . + a 1 8 = 1 8 2 [ 2 * 5 + 1 7 * 4 ] = 7 0 2          

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

y=2x2+x+2.... (i)

dydx=4x+1

Slope of normal

−dxdy=−14x+1

Equation of PQ y - β = −14α+1 (x−α)

It passes (6, 4)

⇒ (4−β) (4α+1)=− (6−α)

4α3+3α2−3α−3=0

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

R (10+α3, 83)

|mAQ|=|mAP|

⇒|45−α|=|32−α|

= 7 not possible ∴α=237.∴7α+3β=23+8=31

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 67k Colleges
  • 1.2k Exams
  • 718k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.