Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

Chlorophyll present in green leaves of plants absorbs light at 4.620 × 1014 Hz. Calculate the wavelength of radiation in nanometers. Which part of the electromagnetic spectrum does it belong to?

7 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: We know that

λ= c/υ Given,

υ = 4.620 × 10¹⁴ Hz

Thus, λ= c/υ = (3.0 × 10⁸ m/s)/ (4.620×10¹⁴ Hz) = 649.4nm

This frequency falls under visible range

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

A hypothetical electromagnetic wave is shown in Fig. 2.2. Find out the wavelength of the radiation

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Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: The wavelength is defined as the distance between two consecutive crests or troughs of a wave, and it is denoted by l .

l = 4*2.16 pm = 8.64 pm

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

Out of electron and proton which one will have, a higher velocity to produce matter waves of the same wavelength? Explain it.

6 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: We have

λ = h/mv

Thus, the equation signifies that in order to have the same wavelength the electron should have higher velocity as the mass of the proton is higher than that of the electron

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter One

A vessel contains 1.6 g of dioxygen at STP (273.15K, 1 atm pressure). The gas is now transferred to another vessel at constant temperature, where pressure becomes half of the original pressure. Calculate

(i) Volume of the new vessel.

10 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

P₁=1 atm

P₂= 1/2=0.5 atm

T₁=273.15 K

V₂=?

&nbs

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

What is the experimental evidence in support of the idea that electronic energies in an atom are quantized?

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Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: The line spectrum associated with any element possesses lines corresponding to specific wavelengths and these lines are obtained as a result of electronic transitions between the energy levels. Hence, the electrons in these le

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

According to de Broglie, matter should exhibit dual behaviour, that is both particle and wave like properties. However, a cricket ball of mass 100 g does not move like a wave when it is thrown by a bowler at a speed of 100 km/h. Calculate the wavelength of the ball and explain why it does not show wave nature.

5 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: As per de Broglie, every object in motion has a wave character i.e. every object/matter have dual nature both particle and wave nature. But the wavelengths associated with ordinary objects are so short (because of their large

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

The Balmer series in the hydrogen spectrum corresponds to the transition from 1n = 2 to 2n = 3,4,. This series lies in the visible region. Calculate the wave number of line associated with the transition in Balmer series when the electron moves to n = 4 orbit. (R_H = 109677 cm^–1).

7 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: We have V = 109677 [1/ni ² - 1/nf² ] cm^-1

Given, n_i = 2, n_f=4

V =109677 [1/4 - 1/16] = 20564.44 cm^-1

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

The electronic configuration of valence shell of Cu is 3d¹⁰4s¹ and not 3d⁹4s² . How is this configuration explained?

6 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: As per the Hund's rule the half filled and fully filled orbital leads to the extra stability due to the symmetry thus fully filled 3d and half filled 4s is preferred.

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

Wavelengths of different radiations are given below :

λ(A) = 300 nm λ(B)= 300µm λ(C) = 3 nm λ (D) = 30 A⁰

Arrange these radiations in the increasing order of their energies.

6 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans:

We know that energy is inversely proportional to the wavelength

Thus, the increasing order of energy is B

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New answer posted•a year ago

Ncert Solutions Chemistry Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Two

An atom having atomic mass number 13 has 7 neutrons. What is the atomic number of the atom?

3 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: The mass number (A) is defined as the sum of the number of protons and neutrons present in the nucleus and the atomic number is defined as the number of protons or electrons present in an atom. Thus A=13, the number of neutron

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Ncert Solutions Chemistry Class 11th

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