Ncert Solutions Chemistry Class 11th

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New answer posted

9 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

ANS- For the emission of electrons from metal the frequency of the striking light should be higher than that of its threshold frequency. We have

h ν = hν 0 + K.E

ν 0 = ν - K.E/h ……. (1)

Given

 ν = 1015 s -1, K.E = 1.988 X 10-19J

Thus (1) gives

ν 0 = 7 x 1014 s -1

Given

λ = 600 nm

ν = c/ λ = 5 x 1014 s -1

 As ν 0 > ν, thus the electrons do not emit.

New answer posted

9 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

ANS-When the beam of light gets exposed to the metal surface then the electrons get emitted from the metal. This effect is said to be photoelectric effect and the emitted electrons are said to be photoelectrons. The result of photoelectric experiment are as follows: -

(i) There is no time gap between the striking of a light beam and the ejection of electrons from the metal surface i.e., electrons emit as soon as a beam of light strikes the metal surface.

(ii) The number of electrons ejected is directly proportional to the intensity of light.

(iii) For every metal there

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New answer posted

10 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

This is a Matching Type Questions as classified in NCERT Exemplar

i                                           d          + 48

ii                                          a  &n

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New question posted

10 months ago

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New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Matching Type Questions as classified in NCERT Exemplar

i )                            1681    3374    – 328

ii )                           a   419     3051     – 48

iii)                   

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New answer posted

10 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

This is a Matching Type Questions as classified in NCERT Exemplar

Be                                                  111

C                                               

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New answer posted

10 months ago

0 Follower 18 Views

A
alok kumar singh

Contributor-Level 10

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Option (ii)

The electron gain enthalpy decreases down the group due to the increase in the atomic size which leads to decrease in the effective nuclear charge.

New answer posted

10 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Option (iii)

The Be has the electronic configuration of [He]2s2 while B has the electronic configuration of [He]2s22p1 . As in Be the outermost orbital i.e. 2s is fully filled thus it provides extra stability to the Be compared to B. Apart from this 2s electron is more penetrated compared to the 2p electron for which 2p electron faces more shielding effect than that of 2s electron.

New answer posted

10 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Option (ii)

The ionization energy depends upon two factors

(a) The effective nuclear charge.

(b)The e- -e repulsions.

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (i)& (iii)

Aluminium is the element which is a metal and good conductor of electricity.

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