Ncert Solutions Chemistry Class 11th
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Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.
(i) 3HCl(aq) + HNO3 (aq) → Cl2 (g) + NOCl (g) + 2H2O (l )
(ii) HgCl2 (aq) + 2KI (aq) → HgI2 (s) + 2KCl (aq)
(iii) Fe2O3 (s) + 3CO (g) → 2Fe (s) + 3CO2 (g)
(iv) PCl3 (l) + 3H2O (l) → 3HCl (aq) + H3 PO3 (aq)
(v) 4NH3 + 3O2 (g) → 2N2 (g) + 6H2O (g)
Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.
(i) 3HCl(aq) + HNO3 (aq) → Cl2 (g) + NOCl (g) + 2H2O (l )
(ii) HgCl2 (aq) + 2KI (aq) → HgI2 (s) + 2KCl (aq)
(iii) Fe2O3 (s) + 3CO (g) → 2Fe (s) + 3CO2 (g)
(iv) PCl3 (l) + 3H2O (l) → 3HCl (aq) + H3 PO3 (aq)
(v) 4NH3 + 3O2 (g) → 2N2 (g) + 6H2O (g)
(i) We can write the given reaction along with their oxidation numbers as-
As, chlorine is oxidised in hydrochloric acid (behaving as reducing agent) -as its oxidation number is increases during the reaction from -1 to 0) and nitric
Upvote 
Balance the following equations by the oxidation number method
(i) Fe2+ + H+ + Cr22–O7 → Cr3+ + Fe3+ + H2O
(ii) I2 + NO3– → NO2 + IO3 –
(iii) I 2 + S2O32– → I– + S4O62–
(iv) MnO2 + C2 O42– → Mn2+ + CO2
Balance the following equations by the oxidation number method
(i) Fe2+ + H+ + Cr22–O7 → Cr3+ + Fe3+ + H2O
(ii) I2 + NO3– → NO2 + IO3 –
(iii) I 2 + S2O32– → I– + S4O62–
(iv) MnO2 + C2 O42– → Mn2+ + CO2
This is a Short answer type question as classified in NCERT Exemplar
(i) We can balance the given equation by oxidation number method-
(a)Balance the increase and decrease in O.N.
(b) Balancing H and O atoms by adding H+ and H2O molecules
(ii) We can balance the given equation
Upvote Calculate the oxidation number of each sulphur atom in the following compounds:
(a) Na2S2O3
(b) Na2S4O6
(c) Na₂SO₃
(d) Na2SO4
Calculate the oxidation number of each sulphur atom in the following compounds:
(a) Na2S2O3
(b) Na2S4O6
(c) Na₂SO₃
(d) Na2SO4
(a) let x= oxidation number of sulphur, and +1 is oxidation number of Na, -2 is oxidation number of O, also we can assume total charge on compound = 0 then solving we get.
+2 + 2x - 6 = 0
x = +2.
(b) let x= oxidation number of sulphu
Upvote Calculate the oxidation number of phosphorus in the following species.
(a) HPO32–
(b) PO43-
Calculate the oxidation number of phosphorus in the following species.
(a) HPO32–
(b) PO43-
This is a Short answer type question as classified in NCERT Exemplar
(i) Let the oxidation number of P in HPO32- be x.
Therefore, +1 + x + (-6) = -2
x = +3
Oxidation number of phosphorus is= +3.
(ii) Let the oxidation number of P in PO43- be x.
Therefore, x + (-8) = -3
x = +5&
Upvote (iii) Dichlorine heptaoxide (Cl2O7 ) in gaseous state combines with an aqueous solution of hydrogen peroxide in acidic medium to give chlorite ion (ClO2– ) and oxygen gas. (Balance by ion electron method)
(iii) Dichlorine heptaoxide (Cl2O7 ) in gaseous state combines with an aqueous solution of hydrogen peroxide in acidic medium to give chlorite ion (ClO2– ) and oxygen gas. (Balance by ion electron method)
We can balance the given reaction by ion electron method as
Cl2O7 (g) + H2O2 (aq) → ClO2- +O2 (acidic medium)
This is a Short answer type question as classified in NCERT Exemplar
Balancing bu ion electron method
2 × { Cl2O7 + 6H+ + 8e- → 2ClO2- + 3H2O
8 × { H2O2 → O2 + 2H+ + 2e-
The balanced c
Upvote Write balanced chemical equation for the following reactions:
(i) Permanganate ion (MnO4 – ) reacts with sulphur dioxide gas in acidic medium to produce Mn2+ and hydrogensulphate ion. (Balance by ion electron method).
(ii) Reaction of liquid hydrazine (N2H4 ) with chlorate ion (ClO3– ) in basic medium produces nitric oxide gas and chloride ion in gaseous state. (Balance by oxidation number method)
(iii) Dichlorine heptaoxide (Cl2O7 ) in gaseous state combines with an aqueous solution of hydrogen peroxide in acidic medium to give chlorite ion (ClO2– ) and oxygen gas. (Balance by ion electron method)
Write balanced chemical equation for the following reactions:
(i) Permanganate ion (MnO4 – ) reacts with sulphur dioxide gas in acidic medium to produce Mn2+ and hydrogensulphate ion. (Balance by ion electron method).
(ii) Reaction of liquid hydrazine (N2H4 ) with chlorate ion (ClO3– ) in basic medium produces nitric oxide gas and chloride ion in gaseous state. (Balance by oxidation number method)
(iii) Dichlorine heptaoxide (Cl2O7 ) in gaseous state combines with an aqueous solution of hydrogen peroxide in acidic medium to give chlorite ion (ClO2– ) and oxygen gas. (Balance by ion electron method)
This is a Short answer type question as classified in NCERT Exemplar
(i) 2Mn0–4 + 5S02 + 2H20 + H+?5HS0–4 + 2Mn2+
Balancing by ion-electron method:
(ii) We can balance the given reaction by oxidation number method-
Balancing by oxidation number method as to make the electron gain and loss
Upvote Nitric acid is an oxidising agent and reacts with PbO but it does not react with PbO2 . Explain why?
Nitric acid is an oxidising agent and reacts with PbO but it does not react with PbO2 . Explain why?
This is a Short answer type question as classified in NCERT Exemplar
Since nitric acid itself is an oxidising agent therefore, it is unlikely that the reaction may occur between PbO2 and nitric acid. However, the acid-base reaction occurs between PbO and nitric acid because PbO is a basic oxide.
Upvote PbO and PbO2 react with HCl according to following chemical equations :
2PbO + 4HCl → 2PbCl2 + 2H2O
PbO2 + 4HCl → PbCl2 + Cl2 + 2H2O
Why do these compounds differ in their reactivity?
PbO and PbO2 react with HCl according to following chemical equations :
2PbO + 4HCl → 2PbCl2 + 2H2O
PbO2 + 4HCl → PbCl2 + Cl2 + 2H2O
Why do these compounds differ in their reactivity?
This is a Short answer type question as classified in NCERT Exemplar
The given compound can differ in reactivity as-Lead is present in +4 oxidation state, whereas the stable oxidation state of lead in PbO is +2. PbO2 thus, can act as an oxidant (oxidising agent) and, therefore, can oxidise chloride i
Upvote MnO42– undergoes disproportionation reaction in acidic medium but MnO4– does not. Give reason.
MnO42– undergoes disproportionation reaction in acidic medium but MnO4– does not. Give reason.
This is a short answer type question as classified in NCERT Exemplar
In MnO42–, Mn is in the highest oxidation state that is +7 hence here manganese cannot undergo oxidation that is why disproportionate is not possible whereas in MnO42- manganese is in +6 oxidation state which can be oxidized a
Upvote The reaction
Cl2 (g) + 2OH– (aq) → ClO– (aq) + Cl– (aq) + H2O (l)
represents the process of bleaching. Identify and name the species that bleaches the substances due to its oxidising action.
The reaction
Cl2 (g) + 2OH– (aq) → ClO– (aq) + Cl– (aq) + H2O (l)
represents the process of bleaching. Identify and name the species that bleaches the substances due to its oxidising action.
This is a Short answer type question as classified in NCERT Exemplar
The given reaction is as below-
Cl2 (g) +2OH-- (aq)→ClO-- (aq)+ Cl-- (aq) + H2O (l)
In the given reaction, oxidation number of Cl increases from 0 (in Cl2) to +1 (in ClO-) and decreases to -1 (in Cl-). Therefor
Upvote