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Ncert Solutions Chemistry Class 11th

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6 months ago

Ncert Solutions Chemistry Class 11th States of Matter

Assertion and Reason:

Directions:

(a) Assertion and reason both are correct statements and reason is correct explanation for assertion.

(b) Assertion and reason both are correct statements but reason is not correct explanation for assertion.

(c) Assertion is correct statement but reason is wrong statement.

(d) Assertion is wrong statement but reason is correct statement.

5.23. Assertion: The dipole-dipole interactionbetween two HCl moleculesis stronger than the London forces.

Reason: Only partial charges are involved
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P
Payal Gupta

Contributor-Level 10

5.23.  (a) The dipole-dipole interaction between two HCl molecules is stronger than the London forces but is weaker than ion-ion interaction because only partial charges are involved.

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th Redox Reactions

8.17. Consider the reactions:
(a) H3PO2(aq) + 4AgNO3(aq) + 2H2O(l) → H3PO4(aq) + 4Ag(s) + 4HNO3(aq)
(b) H3PO2(aq) + 2CuSO4(aq) + 2H2O(l) → H3PO4(aq) + 2Cu(s) + H2SO4(aq)
(c) C6H5CHO(l) + 2[Ag(NH3)2]+(aq) + 3OH–(aq→ C6H5COO–(aq) + 2Ag(s) + 4NH3(aq) + 2H2O(l)
(d) C6H5CHO(l) + 2Cu2+(aq) + 5OH–(aq) → No change observed
What inference do you draw about the behaviour of Ag+ and Cu2+ from these reactions?
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V
Vishal Baghel

Contributor-Level 10

Reactions (a) and (b) indicate that H3PO2  (hypophosphorous acid) is a reducing agent and thus reduces both AgNO3 and CuSO4 to Ag and Cu respectively. Conversely, both AgNO3 and CuSO4 act as oxidising agent and thus oxidise H3PO2to H3PO4  (orthophosphoric acid) Reaction (c) suggests that [Ag (NH3)2]+ oxidises C6H5CHO (benzaldehyde) to C6H5COO–  (benzoate ion) but reaction (d) indicates that Cu2+ ions cannot oxidise C6H5CHO to C6H5COO–. Therefore, from the above reactions, we conclude that Ag+ ion is a strong deoxidising agent than Cu2+ ion.

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th Redox Reactions

8.16. Why does the following reaction occur?

XeO64– (aq) + 2F– (aq) + 6H+(aq) → XeO3(g)+ F2(g) + 3H2O(l)

What conclusion about the compound Na4XeO6 (of which XeO64– is a part) can be drawn from the reaction?
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V
Vishal Baghel

Contributor-Level 10

XeO64−? oxidizes F− and F− reduces XeO64−?
Hence, the given reaction occurs.
The oxidation number of Xe decreases from +8 to +6. The oxidation number of F increases from -1 to 0.
Thus,  Na4? XeO6? is a stronger oxidising agent than F−.

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th Redox Reactions

8.15. Justify giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic acid is the best reductant.
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Vishal Baghel

Contributor-Level 10

Fluorine oxidizes chloride ion to chlorine, bromide ion to bromine and iodide ion to iodine respectively.
F2? + 2Cl− → 2F− + Cl2?
F2? + 2Br− → 2F− + Br2?
F2? + 2I− → 2F− + I2?

Chlorine oxidizes bromide ion to bromine and iodide ion to iodine.
Cl2? + Br− → 2Cl− + Br2?
Cl2? + I− → 2Cl− + I2?

Bromine oxidizes iodide ion to iodine.
Br2? + I− → 2Br− + I2?

But bromine and chlorine cannot oxidize fluoride to fluorine. Hence, fluorine is the best oxidizing agent amongst the halogens. The decreasing order of the oxidizing power of halogens is F2? >Cl2? >Br2? >I2?  

HI and HBr can reduce sulphuric acid

...more

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th Redox Reactions

8.14. Consider the reactions:

Why does the same reductant, thiosulphate react differently with iodine and bromine?
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Vishal Baghel

Contributor-Level 10

The average O.N. of S in S2O32- is +2 while in S4O62- it is + 2.5. The O.N. of S in SO42- is +6. Since Br2 is a stronger oxidising agent than I2, it oxidises S of S2O32- to a higher oxidation state of +6 and hence forms SO42- ion. I2, however, being weaker oxidising agent oxidises S of S2O32- ion to a lower oxidation of +2.5 in S4O62- ion. It is because of this reason that thiosulphate reacts differently with Br2 and I2.

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th Redox Reactions

8.13. Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions.
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V
Vishal Baghel

Contributor-Level 10

Substance oxidised

Substance reduced

Oxidising agent

Reducing agent

(a) C6H12O6

AgBr

C6H12O6

(b) HCHO

[Ag (NH3)2]+ 

[Ag (NH3)2]+ 

HCHO

(c) HCHO

Cu2+ 

HCHO

(d) N2H4

H2O2

N2H4

(e) Pb

PbO2

Pb

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th States of Matter

5.22. Critical temperature for CO2 and CH4 are 31.1°C and -81.9°C respectively. Which of these has stronger intermolecular forces and why?
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P
Payal Gupta

Contributor-Level 10

5.22. Higher the critical temperature, more easily the gas can be liquefied, i.e., greater are the intermolecular forces of attraction. Hence, CO2 has stronger intermolecular forces than CH4.

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th Redox Reactions

8.12. How do you account for the following observations?
(a) Though alkaline potassium permanganate and acidic potassium permanganate both are used as oxidants, yet in the manufacture of benzoic acid from toluene we use alcoholic potassium permanganate as an oxidant. Why? Write a balanced redox equation for the reaction.

(b) When concentrated sulphuric acid is added to an inorganic mixture containing chloride, we get colourless pungent smelling gas HCl, but if the mixture contains bromide then we get red vapour of bromine. Why?
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V
Vishal Baghel

Contributor-Level 10

(a) Toluene can be oxidised to benzoic acid in acidic, basic and neutral media according to the following redox equations:

In the laboratory, benzoic acid is usually prepared by alcoholic KMnO4 oxidation of toluene. However, in industry alcoholic KMnO4 is preferred over acidic or alkaline KMnO4 because of the following reasons:
(i) The cost of adding an acid or the base is avoided because in the neutral medium, the base (OH- ions) are produced in the reaction itself.
(ii) Since reactions occur faster in homogeneous medium than in heterogeneous medium, therefore, alcohol helps in mixing the two reactants, i.e., KMnO4

...more

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th States of Matter

5.21. In terms of Charles' law explain why -273°C is the lowest possible temperature.
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P
Payal Gupta

Contributor-Level 10

5.21. At -273°C, volume of the gas becomes equal to zero, i.e., the gas ceases to exist.

 

New answer posted

6 months ago

Ncert Solutions Chemistry Class 11th Redox Reactions

8.11. Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if oxidising agent is in excess. Justify this statement giving three illustrations.
0 Follower 34 Views

V
Vishal Baghel

Contributor-Level 10

The three examples are:

(i) When excess P4?   (reducing agent) reacts with F2? (oxidizing agent),  PF3?  is produced in which P has +3 oxidation number.
                        P4? (excess) + F2? → PF3?
But if fluorine is in excess,  PF5?  is formed in which P has oxidation number of +5.
                        P4? ? + F2? (excess) → PF5?

(ii) Oxidizing agent is oxy

...more

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