Ncert Solutions Chemistry Class 11th
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5.16. Pay load is defined as the difference between the mass of the displaced air and the mass of the balloon. Calculate the pay load when a balloon of radius 10 m, mass 100 kg is filled with helium at 1.66 bar at 27°C (Density of air = 1.2 kg m-3 and R = 0.083 bar dm3 K-1 mol-1).
5.16. Pay load is defined as the difference between the mass of the displaced air and the mass of the balloon. Calculate the pay load when a balloon of radius 10 m, mass 100 kg is filled with helium at 1.66 bar at 27°C (Density of air = 1.2 kg m-3 and R = 0.083 bar dm3 K-1 mol-1).
5.16. Radius of the balloon = 10 m
Therefore, volume of the balloon = (4/3)? r3 = (4/3) x (22/7) x (10 m)3
= 4190.5 m3
Volume of He filled at 1.66 bar and 27 °C = 4290.5 m3
To calculate the mass of He,
PV = nRT = (w/M) RT, where M is molar mass of He i.e. 4 g per mole or 4 x 10-3 kg mol-1
=> w =&nbs
Upvote 
5.15. Calculate the total pressure in a mixture of 8g of oxygen and 4g of hydrogen confined in a vessel of l dm3 at 27°C. R = 0.083 bar dm3 K-1 mol-1.
5.15. Calculate the total pressure in a mixture of 8g of oxygen and 4g of hydrogen confined in a vessel of l dm3 at 27°C. R = 0.083 bar dm3 K-1 mol-1.
5.15. Molar mass of O2 = 32 g/mol
It means, 8 g of O2 has 8/32 mol = 0.25 mol
Molar mass of H2 = 2 g/mol
It means, 4 g of H2 has 4/2 mol = 2 mol
Therefore, total number of moles, n = 2 + 0.25 = 2.25 mol
Given, V = 1dm3, T = 27°C = 300 K, R = 0.083 bar dm3 K-1 mol-1
Applying PV = nRT,
P = nRT / V
&nb
Upvote 5.14. How much time would it take to distribute one Avogadro number of wheat grains if 1010 grains are distributed each second?
5.14. How much time would it take to distribute one Avogadro number of wheat grains if 1010 grains are distributed each second?
5.14. Time taken to distribute 1010 wheat grains = 1s
Time taken to distribute Avogadro number of wheat grains = (1s x 6.022 x 1023) / 1010
= 6.022 x 1013 s
= (6.022 x 1013 / 60 x 60 x 24 x 365) year
= 1.9 x 106 years
Upvote 5.13. Calculate the total number of electrons present in 1.4 g of dinitrogen gas.
5.13. Calculate the total number of electrons present in 1.4 g of dinitrogen gas.
5.13. Molecular mass of N2 = 28g
28 g of N2 has No. of molecules = 6.022 x 1023
1.4 g of N2 has No. of molecules = (6.022 x 1023 x 1.4 g)/28 g= 3.011 x 1022 molecules.
Atomic No. of Nitrogen (N) = 7
1 molecule of N2 has electrons = 7 x 2 = 14
3.011
Upvote 5.12. Calculate the temperature of 4.0 moles of a gas occupying 5 dm3 at 3.32 bar (R = 0.083 bar dm3 K-1 mol-1).
5.12. Calculate the temperature of 4.0 moles of a gas occupying 5 dm3 at 3.32 bar (R = 0.083 bar dm3 K-1 mol-1).
5.12. Given,
P= 3.32 bar
V= 5 dm3
n= 4 mol
R= 0.083 bar dm3 K-1 mol-1
PV = nRT
Or T = PV / nR = 3.32 x 5 dm3 / (4.0 mol x 0.083 bar dm3 K-1 mol-1)
= 50 K
Upvote 9.56. How is dihydrogen prepared from water by using a reducing agent?
9.56. How is dihydrogen prepared from water by using a reducing agent?
9.56. Dihydrogen is prepared from water by the action of alkali metals like Na and K which is a strong reducing agent.
2Na + 2H2O → 2NaOH + H2
2K + 2H2O → 2KOH + H2
Upvote 9.55. Give two advantages of using hydrogen over gasoline as a fuel.
9.55. Give two advantages of using hydrogen over gasoline as a fuel.
9.55. 1. High heat of combustion.
2. It is pollution free.
Upvote 9.54. What is meant by hard water? How come boiling remove the temporary hardness of water?
9.54. What is meant by hard water? How come boiling remove the temporary hardness of water?
9.54. Water which does not produce lathers with soap is known as hard water. Hardness is due to the presence of bicarbonates, sulphates and chlorides of Ca2+ and Mg2+.
On boiling, the bicarbonates of calcium and magnesium decompose to insoluble carbonate which can be removed by filtration.
Upvote 9.53. In water molecule, O is SP3 hybridized. Due to stronger lone pair-lone pair repulsion than bond pair-bond pair repulsions, the H-O-H bond angle decreases from 109.5° to 104.5°. Thus, water is bent molecule.
Upvote 9.52. What are interstitial hydrides? Give two examples. Write two uses of interstitial hydrides.
9.52. What are interstitial hydrides? Give two examples. Write two uses of interstitial hydrides.
9.52. Many transition and inner-transition metals absorb hydrogen into the interstices of their lattices to yield metal like hydrides also called the interstitial hydrides. These hydrides are generally non stoichiometric and their composition vary with temperature and pressure.
For example, TiH1
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