Ncert Solutions Chemistry Class 11th

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Payal Gupta

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3.1. The basic theme of organisation of elements in the periodic table is to simplify, systematize and classify the elements based on their similarities in properties. This arrangement makes it easier for us to group the elements and makes it less confusing to present the periodic table.

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Payal Gupta

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1.51. In 1808, Dalton published 'A New System of Chemical Philosophy', in which he proposed the following:

1. Matter consists of indivisible atoms.

2. All atoms of a given element have identical properties, including identical mass. Atoms of different elements differ in mass.

3. Compounds are formed when atoms of different elements combine in a fixed ratio.

4. Chemical reactions involve reorganisation of atoms. These are neither created nor destroyed in a chemical reaction.

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Payal Gupta

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1.50. Carbon-12 isotope is the most abundant isotope of carbon and has been chosen as the standard. Since C-12 is used as the standard atom, one atomic mass unit is defined as one-twelfth of the mass of one carbon – 12 atoms. This is because it has an equal number of protons and neutrons (6) and makes up the majority of matter.

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Payal Gupta

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1.49. The empirical mass of ethene is half of its molecular mass. The empirical formula represents the simplest whole-number ratio of various atoms present in a compound.

Molecular Formula = n * Empirical formula

Empirical formula of Ethene = C2H4

Empirical Formula Mass = 14 amu= ½ Molecular Mass of Ethene

The ratio of Carbon and Hydrogen in the empirical formula is 1: 2.

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Payal Gupta

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1.48. 

Molarity

Molality

The molarity of a given solution is defined as the total number of moles of solute per litre of solution.

Molality is defined as the total moles of a solute contained in a kilogram of a solvent.

The mathematical expression is-

M = number of moles of the solute /Volume of solution given in terms of litres.

M = (g ? 1000)/(W ? V).

The mathematical expression is-

m = Numbers of moles of solute/Mass of solvent in kgs

m = (g ? 1000)/(W ? m).

Depends on the volume of the whole solution.

Depends on the mass of the solvent.

Unit sign expressed as (M).

Unit sign expressed as (m).

Molarity has a unit of mol/litre.

Molality has units of mol/kg.

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Payal Gupta

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1.47. These rules for determining the number of significant figures are stated below:

(1) All non-zero digits are significant. For example, in 285 cm, there are three significant figures and in 0.25 mL, there are two significant figures.

(2) Zeros preceding to first non-zero digit are not significant. Such zero indicates the position of decimal point. Thus, 0.03 has one significant figure and 0.0052 has two significant figures.

(3) Zeros between two non-zero digits are significant. Thus, 2.005 has four significant figures.

(4) Zeros at the end or right of a number are significant, provided they are on the right side of the decimal po

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1.46.  (c) both a and b

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Payal Gupta

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1.45.  (d) 36 g of water

CH4 + 2O2 → CO2 + 2H2O

1 mol of CH4 reacts with 1 mol O2 of to produce 2 moles of H2O

It means that 16g of CH4 reacts with oxygen to produce (2x18)= 36g of water

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Payal Gupta

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1.44.  (b) Candela

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Payal Gupta

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1.43. (c) The mass of 1 mole of C-12 atoms = 12 g

1 mole of C- atoms = 6.022 * 1023 atoms

The mass of 1 atom of C-12 = 12 / (6.022 * 1023)

= 1.99 * 10–23 g

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