Ncert Solutions Chemistry Class 12th

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct Option: (iv)

The cell constant is described as the ratio of the length of the object and the area of cross-section. It can be written as follow

G= l A

As l and A remains constant for an object it can be inferred that the cell constant for a conductivity cell remains constant for a cell.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Correct options: A and D 

Elementary reaction: It is a reaction that occurs in a single step.

Here we must understand about the Order and Molecularity.

Molecularity of a reaction = number of reacting species (collide to bring a chemical reaction).

Discussing about the Order, Rate law is used in Order and how do we equate shall be seen in the next step

rate = k [A] α [B] β

For a balanced chemical equation of an elementary reaction Order and Molecularity is same and can never be 0. 

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Correct Option: (iii)

 Ans: Given: One mole of aluminium

Calculate the number of electrons required to convert Al2O3 to Al

It is the charge required to obtain one mole of aluminium from Al2O3

The dissociation of aluminium oxide is as follows;

Al2O3→2Al3++3O2−

Al3++3e→Al

Therefore 3Fcharge is required to obtain one mole of aluminum from Al2O3.

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct Option: (i)

According to the given table, has the most negative value among the given species. So

Cr3+ is the most stable oxidized species.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Correct options : A, C and D.

Rate law = Experimental rate of the reaction

Suppose aA + bB→cC + dD

Then rate = k [A] α [B] β

Here instead of using complex reaction we use elementary reaction which gets solved in one step

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct Option: (iv)

is the highest positive value among the given species. So Mn2+ is the most stable ion in its reduced form.

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct Option: (iii)

According to the electrochemical series, the lower the reduction potential higher is the reducing power.

Therefore, the order of reducing power is Mn2+ < Cl < Cr3+ < Cr

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct Option: (iii)

According to the electrochemical series higher the positive value of standard reduction potential of metal ion, the higher is the oxidizing power

Therefore, MnO4 is the strongest oxidizing agent.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

Incorrect order results from a balanced chemical equation. KClO3 + 6FeSO4 + 3H2SO4→KCl + 3H2O + 3Fe2 (SO4)3

This reaction is complex and occurs in several steps. The order is determined by the slowest in the reactions

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct Option: (ii)

According to the electrochemical series and standard reduction potential of metal, the higher the negative value of standard reduction potential stronger will be the reducing agent

In the given options, the standard reduction potential of chromium has the highest value so it is the strongest reducing agent.

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