Ncert Solutions Chemistry Class 12th
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New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: According to Faraday's second law of electrolysis, the amount of different substances liberated keeping the electricity flow same through the electrolytic solution is directly proportional to the equivalent weight.
=
E1and E2 have different values. Therefore, the mass of copper and silver deposited will be different
New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Question as classified in NCERT Exemplar
The concentration of the reactants does not change with time in a zero- order reaction, and the rate of concentration remains constant.
New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: At the stage of equilibrium E? Cell =0. So according to the relation,
ΔrG =−nFEcell
ΔrG =−n*F*0
ΔrG =0
New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Question as classified in NCERT Exemplar
Let order of reaction be = n
rate = k [A]n- (i)
27r = k [3A]n- (ii)
Divide (ii) by (i)
= k [3A]nn
3n = 27
n = 3
New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: E? Cell can never be zero. For a feasible reaction E? Cell should be positive or ΔrGshould be negative and at the stage of equilibrium, both of these parameters are zero.
New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Question as classified in NCERT Exemplar
The order and molecularity of elementary reactions are the same. As a result of a single collision between two molecules or ions, a complicated process occurs. A reaction mechanism is a set of elementary reactions.
New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans:No, the difference in potentials of the electrodes is measured. A reference electrode is to be taken while measuring the electrode potential of the electrode.
New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Question as classified in NCERT Exemplar
Experimentally, the reaction's rate law can be calculated.
Step 1
2NO (g) + O2 (g)→2NO2 (g)
O2 (g) is taken in excess
x molecules of NO number reacting with excess of O2
r = k [NO]x
Step 2
2NO (g) + O2 (g)→2NO2 (g)
When 2No (g)is taken in excess
Y molecules of O2 reacting with excess of [NO]
rate = k [O2]y
rate = k [NO]x [NO]y
New answer posted
5 months agoContributor-Level 10
This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans: The relation between Gibbs free energy and the emf of the cell is as follows;
ΔG=−nFEcell
E cell s the cell potential
is the standard emf of the cell
Maximum work obtained from the galvanic cell is nFE .
New answer posted
5 months agoContributor-Level 10
This is a Short Answer Type Question as classified in NCERT Exemplar
Given: Order of the reaction = 0
We know that a zero order reaction is a chemical reaction that occurs regardless of the reactant's concentration.
The rate law of 2A + B→C is
r = k [A]0 [B]0
For a zero- order reaction
r = k
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