Ncert Solutions Chemistry Class 12th

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V
Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: According to Faraday's second law of electrolysis, the amount of different substances liberated keeping the electricity flow same through the electrolytic solution is directly proportional to the equivalent weight.

ω 1 ω 2 = E 1 E 2

E1and E2 have different values. Therefore, the mass of copper and silver deposited will be different

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5 months ago

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

The concentration of the reactants does not change with time in a zero- order reaction, and the rate of concentration remains constant.

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: At the stage of equilibrium E? Cell =0. So according to the relation,

ΔrG =−nFEcell

ΔrG =−n*F*0

ΔrG =0

New answer posted

5 months ago

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

Let order of reaction be = n

rate = k [A]n- (i)

27r = k [3A]n- (ii)

Divide (ii) by (i)

27 r r  =  27 r r   k [3A]nn

3n = 27

n = 3

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5 months ago

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: E? Cell can never be zero. For a feasible reaction E? Cell should be positive or ΔrG°should be negative and at the stage of equilibrium, both of these parameters are zero.

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

The order and molecularity of elementary reactions are the same. As a result of a single collision between two molecules or ions, a complicated process occurs. A reaction mechanism is a set of elementary reactions.

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans:No, the difference in potentials of the electrodes is measured. A reference electrode is to be taken while measuring the electrode potential of the electrode.

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

Experimentally, the reaction's rate law can be calculated.

Step 1

2NO (g) + O2 (g)→2NO2 (g)

O2 (g) is taken in excess

x molecules of NO number reacting with excess of O2

r = k [NO]x

 

Step 2

2NO (g) + O2 (g)→2NO2 (g)

When 2No (g)is taken in excess

 

Y molecules of O2 reacting with excess of [NO]

 

rate = k [O2]y

rate = k [NO]x [NO]y

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Vishal Baghel

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: The relation between Gibbs free energy and the emf of the cell is as follows;

ΔG=−nFEcell

 E ° cell s the cell potential

is the standard emf of the cell

Maximum work obtained from the galvanic cell is nFE ° .

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

Given: Order of the reaction = 0

We know that a zero order reaction is a chemical reaction that occurs regardless of the reactant's concentration.

The rate law of 2A + B→C is

r = k [A]0 [B]0

For a zero- order reaction

r = k

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