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Ncert Solutions Chemistry Class 12th

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New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

Which of the following is an isoelectronic pair? 

(i) ICl2 , ClO2

(ii) BrO2-  , BrF2

(iii) ClO2 , BrF

(iv) CN- , O3
0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (ii)

BrO2- (35+2*8+1=52) and BrF2+  (35+2*9−1=52)

52 electrons are present in both 

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.

(i) ClO4-  >  IO4-  >  BrO4- 

(ii) IO4-  >  BrO4-  >  ClO4-  

(iii) BrO4-  >  IO4-  >  ClO4-  

(iv) BrO4-  >  ClO4-  >  IO4- 
0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii)

The ability of a substance to be decreased is known as its reduction potential. As the substance's reduction potential rises, so does its power to reduce. It signifies the chemical's oxidising power (the ability of the material to cause other substances to lose electrons, which is known as oxidising power) grows.

As a result, the oxidising power is listed in decreasing order BrO4-  >  IO4-  >  ClO4-  

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

In solid state PCl5 is a _________. 

(i) Covalent solid 

(ii) Octahedral structure 

(iii) Ionic solid with [PCl6]+   octahedral and [PCl4]−  tetrahedral

(iv) Ionic solid with [PCl4]+  tetrahedral and [PCl6]−  octahedral
0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iv)

The ionic bonding promotes the crystalline structure of PCl5 in the solid state by attempting to exist as oppositely charged ions like  [PCl4]+  and  [PCl6]− .  Also,   [PCl4]+  and  [PCl6]−  are tetrahedral and octahedral, respectively. These structures fit together well, giving the solid structure extra stability.

 

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

In the preparation of compounds of Xe, Bartlett had taken O2+ PtF6−  as a base compound. This is because 

(i) Both O2 and Xe have the same size. 

(ii) Both O2 and Xe have the same electron gain enthalpy. 

(iii) Both O2 and Xe have almost the same ionisation enthalpy. 

(iv) Both O2 and Xe are gases.
0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii)

Bartlett noticed that Xenon's first ionisation potential is nearly identical to that of oxygen and used Born-Haber calculations to predict the presence of a stable compound: Xe+ Pt F6- 

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with NH3 an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from _________. 

(i) – 3 to +3 

(ii) – 3 to 0 

(iii) – 3 to +5 

(iv) 0 to – 3
0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iv)

MnO2 ( Black )+4HCl→MnCl2+2H2O+Cl2

Greenish yellow color

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

Hot conc. H2SO4 acts as moderately strong oxidising agent. It oxidises both metals and nonmetals. Which of the following element is oxidised by conc. H2SO4 into two gaseous products?

(i) Cu

(ii) S

(iii) C 

(iv) Zn
0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii)

C+2H2SO4→CO2+2SO2+2H2O

Conc. H2SO4 oxidises C to produce two gaseous products.

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

Which of the following are peroxoacids of sulphur? 

(i) H2SO5 and H2S2O8

(ii) H2SO5 and H2S2O7

(iii) H2S2O7 and H2S2O8

(iv) H2S2O6 and H2S2O7
0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (i)

Peroxy linkage refers to the presence of a bond between oxygen and oxygen (O-O) in a molecule.

Only H2S2O6 and H2S2O7 of the sulphur oxoacids above have a peroxy linkage.

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

Which of the following is not tetrahedral in shape? 

(i) NH4+ 

(ii) SiCl4 

(iii) SF4 

(iv) SO42−
0 Follower 9 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii)

The C-atom in the CO32-  ion undergoes sp2 hybridization. BF4, NH4+  and SO42-  have a tetrahedral structure, whereas it has a triangular planar structure.

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

The oxidation state of central atom in the anion of compound NaH2PO2 will be ______.

(i) +3 

(ii) +5 

(iii) +1 

(iv) –3
0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii)

Na (H2)PO2

1+ (2x+1)+ x +2 (−2)=0

x−1=0

x=1

New answer posted

5 months ago

Ncert Solutions Chemistry Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

In the preparation of HNO3, we get NO gas by catalytic oxidation of ammonia. The moles of NO produced by the oxidation of two moles of NH3 will be______. 

(i) 2 

(ii) 3 

(iii) 4 

(iv) 6
0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (i)

The catalytic oxidation of ammonia produces NO gas, which is used to make HNO3. 4 moles of NH3 created 4 moles of NO in the equation below. As a result, the moles of NO produced by oxidising two moles of NH3 will be two moles.

4NH3 + 5O2→4NO + 6H2O.

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