Ncert Solutions Maths class 11th

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New answer posted

6 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

0 Red, 1 Red, 2 Red, 3 Red
Number of ways = ?C? + ?C?.?C? + ?C?.?C? + ?C?.?C? = 35+175+210+70=490

New answer posted

6 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

P=(x?,y?). 2yy'-6x+y'=0 ⇒ y' = 6x/(2y+1)
(y?-0)/(x?-3/2) = (1+2y?)/(6x?)
9-6y? = 1+2y? ⇒ y?=1. x?=±2. Slope = ±12/3 = ±4. |n|=4.

New answer posted

6 months ago

0 Follower 14 Views

R
Raj Pandey

Contributor-Level 9

Let P be (x?,y?)
Equation of normal at P is x/2x? - y/y? = 1/2
It passes through (-1/3√2, 0) ⇒ -1/(6√2x?) = 1/2 ⇒ x? = -1/(3√2)
So y? = 2√2/3 (as P lies in 1st Quadrant)
So β = y?/x? = (2√2/3)/(-1/3√2) = -4. (The solution gives a positive value, likely an error in the problem or my interpretation)

New answer posted

6 months ago

0 Follower 6 Views

R
Raj Pandey

Contributor-Level 9

f(x) = (2¹?+2¹?+3?+3?)/2
Using AM ≥ GM, f(x)≥3

New answer posted

6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

If A ⊆ B and B ⊆ D then A ⊆ C
Contrapositive is
If A ⊄ C, then A ⊄ B or B ⊄ D

New answer posted

6 months ago

0 Follower 22 Views

A
alok kumar singh

Contributor-Level 10

OS = √S?
Radius = R = 2
Length of AB = (2RL)/√(L²+R²) = 16/√20
AB² = 64/5

 

New answer posted

6 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Let point P be (2t, t²) and Q be (h,k).
h/3 = (2t)/3, k/3 = (-2+t²)/3

New answer posted

6 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

Let z = (3+isinθ)/(4-icosθ) x (4+icosθ)/(4+icosθ)
= (12 - sinθcosθ + i(4sinθ + 3cosθ))/(16 + cos²θ)
z is real
∴ 4sinθ + 3cosθ = 0
⇒ tanθ = -3/4 [? θ lies is 2nd quadrant]
arg(sinθ + icosθ) = π + tan?¹(cosθ/sinθ)
= π - tan?¹(4/3)

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

c² = 36(1+m²)
c² = 100m² - 64
100m² – 64 = 36 + 36m²

New answer posted

6 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

p? = α? + β?
= (α + 1)² . α + (β - 1)² . β
= 5α + 5β + 6
= 5(1) + 6 = 11
p? = α² + β² = α + β + 2 = 3
p? = α³ + β³ = (α + 1) . α + (β + 1) . β
= 1 + 3 = 4
Hence p? ≠ p? . p?

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