Ncert Solutions Maths class 11th
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New answer posted
a month agoContributor-Level 10
If A ⊆ B and B ⊆ D then A ⊆ C
Contrapositive is
If A ⊄ C, then A ⊄ B or B ⊄ D
New answer posted
a month agoLet the tangents drawn from the origin to the circle,
touch it at the points
and
. Then
is equal to:
Contributor-Level 10
OS = √S?
Radius = R = 2
Length of AB = (2RL)/√(L²+R²) = 16/√20
AB² = 64/5

New answer posted
a month agoNew answer posted
a month agoContributor-Level 10
Let z = (3+isinθ)/(4-icosθ) x (4+icosθ)/(4+icosθ)
= (12 - sinθcosθ + i(4sinθ + 3cosθ))/(16 + cos²θ)
z is real
∴ 4sinθ + 3cosθ = 0
⇒ tanθ = -3/4 [? θ lies is 2nd quadrant]
arg(sinθ + icosθ) = π + tan?¹(cosθ/sinθ)
= π - tan?¹(4/3)
New answer posted
a month agoContributor-Level 10
p? = α? + β?
= (α + 1)² . α + (β - 1)² . β
= 5α + 5β + 6
= 5(1) + 6 = 11
p? = α² + β² = α + β + 2 = 3
p? = α³ + β³ = (α + 1) . α + (β + 1) . β
= 1 + 3 = 4
Hence p? ≠ p? . p?
New answer posted
a month agoContributor-Level 10
Given log?/? x + log?/? x + log?/? x + . 20 times = 460
⇒ (2+3+4+.+21)log?x = 460
⇒ (20/2)(2+21)log?x = 460
⇒ log?x = 2
⇒ x = 49
New answer posted
a month agoContributor-Level 10
a? + a? = 4 ⇒ a? + a?r = 4
a? + a? = 16 ⇒ a?r² + a?r³ = 16
⇒ r = ±2
r = 2 ⇒ a? = 4/3
r = -2 ⇒ a? = -4
Σ(i=1 to 9) a? = (a(r?-1))/(r-1) = (-4)((-2)? - 1)/(-2-1)
= 4/3 (-513) = 4λ
⇒ λ = -171
New answer posted
a month agoContributor-Level 10
A → 5Q; B → 5Q; C → 5QA
A?, A?, A?, A?, A?; B?, B?, B?, B?, B?; C?, C?, C?, C?, C?
A?A?A?B?C? → ?C? * ?C? * ?C? = 750
A?A?B?B?C? → ³C? * ?C? * ?C? = 1500
∴ Total = 2250
New answer posted
a month agoContributor-Level 10
Slope AB = (k-α)/(h-2α) = -1
⇒ α = (k+h)/3
also (β+2α)/2 = h, (β+α)/2 = k
α = 2h - 2k
From (1) and (2)
(h+k)/3 = 2h - 2k
⇒ 5h = 7k
⇒ 5x = 7y

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