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Physics Gravitation

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2 weeks ago

Physics Gravitation Class 11th

Consider the following two statements .

(A)The gravitational force on a particle inside a spherical shell is zero.

(B) Total mechanical energy of a body on earth's surface may be positive.

Which of the following options is correct?

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alok kumar singh

Contributor-Level 10

Inside a spherical shell gravitational field is zero, so net force acting on a particle placed inside it is also zero.

Total energy of a bound system is always negative.

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2 weeks ago

Physics Gravitation Class 11th

The potential energy of a body of mass 3 kg on the surface of a planet is 54 joule. The escape velocity will be

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Raj Pandey

Contributor-Level 9

By given $U = 54 joule m = 3 kg$

By conservation of mechanical energy law

$(K + U)$ Earth surface $= (K + U) \infty$

$\frac{1}{2} m v^{2} + (- 54 J) = 0 + 0$

$\frac{1}{2} m v^{2} = 54$

$3 v^{2} = 108$

$v^{2} = \frac{108}{3} = 36$

v= 6m/s

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Physics Gravitation Class 11th

Two artificial satellites of masses $m_{1}$ and $m_{2}$ are moving with speeds $v_{1}$ and $v_{2}$ in orbits of radii $r_{1}$ and $r_{2}$ , respectively. If r₁>r₂ then which of the following statements is true

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Raj Pandey

Contributor-Level 9

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New answer posted

2 weeks ago

Physics Gravitation Class 11th

Determine the energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 3R

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Vishal Baghel

Contributor-Level 10

$U_{i} = - \frac{G M m}{R}$

${(T . E .)}_{f} = - \frac{G M m}{8 R}$

$\Rightarrow E n e r g y = {(T . E)}_{f} - (U_{i})$

$= \frac{7 G M m}{8 R}$

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2 weeks ago

Physics Gravitation Class 11th

Suppose the gravitational force varies inversely as the $n^{t h}$ power of distance. Then, time period of a planet in circular orbit of radius R around the sum will be proportional to

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alok kumar singh

Contributor-Level 10

Given $F \propto \frac{1}{r^{n}}$

$m ω^{2} R = \frac{K}{R^{n}}$

$? \frac{m . 4 π^{2} R}{T^{2}} = \frac{K}{R^{n}}$

$? T^{2} \propto R^{n + 1}$

$T \propto R^{\frac{n + 1}{2}}$

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2 weeks ago

Physics Gravitation Class 11th

A particle moves in a circular orbit of radius r under a central attractive force F = $- \frac{k}{r},$ k is constant. The time period of its motion is proportional to

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Vishal Baghel

Contributor-Level 10

$F = m r ω^{2} = \frac{k}{r}$

$\begin{array}{l} \Rightarrow ω \propto \frac{1}{r} \\ \Rightarrow T \propto r \end{array}$

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New answer posted

2 weeks ago

Physics Gravitation Class 11th

Consider the following two statements .

(A)The gravitational force on a particle inside a spherical shell is zero.

(B) Total mechanical energy of a body on earth's surface may be positive.

Which of the following options is correct?

0 Follower 1 View

alok kumar singh

Contributor-Level 10

Inside a spherical shell gravitational field is zero, so net force acting on a particle placed inside it is also zero.

Total energy of a bound system is always negative.

0 0

New answer posted

2 weeks ago

Physics Gravitation Class 11th

A man is sitting in a boat which is floating in a pond. If the man drink some water from the pond, what will happen to the level of water in the pond?

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alok kumar singh

Contributor-Level 10

Since the water removed from the pond will be equal to the water displacement by the (man + boat) system, the level of water in the pond remains the same.

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New answer posted

2 weeks ago

Physics Gravitation Class 11th

Gravitational force between two point masses is found to be F when both are in vacuum. If both the masses are immersed in water, new gravitational force will be:

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alok kumar singh

Contributor-Level 10

Gravitational force does not depend on the surrounding medium.

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2 weeks ago

Physics Gravitation Class 11th

In the reported figure of earth, the value of acceleration due to gravity is same at point A and C but it is smaller than that of its value at point B (surface of the earth). The value of OA: AB will be x : y. The value of x is…………

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alok kumar singh

Contributor-Level 10

$\frac{G M}{{(3 R / 2)}^{2}} = \frac{G M}{R^{3}} * r$

$\Rightarrow O A = \frac{4 R}{9} = r$

$A B = R - \frac{4 R}{9} = \frac{5 R}{9} \Rightarrow O A : A B = 4 : 5 = x : y \Rightarrow x = 4$

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