Physics Gravitation

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New question posted•a year ago

<p><strong>Consider two solid spheres of radii <span class="mathml" contenteditable="false"> <math> <msub> <mrow> <mrow> <mi>R</mi> </mrow> </mrow> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> </msub> <mo>=</mo> <mn>1</mn> <mtext> </mtext> <mi mathvariant="normal">m</mi> </math> </span><math><msub><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msub><mtext></mtext></math>&nbsp;, <span class="mathml" contenteditable="false"> <math> <msub> <mrow> <mrow> <mi>R</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> <mo>=</mo> <mn>2</mn> <mi>m</mi> </math> </span><math><msub><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msub></math>&nbsp;and masses <span class="mathml" contenteditable="false"> <math> <msub> <mrow> <mrow> <mi>M</mi> </mrow> </mrow> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> </msub> </math> </span><math><msub><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msub></math>&nbsp;and<span class="mathml" contenteditable="false"> <math> <msub> <mrow> <mrow> <mi>M</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> </math> </span> <math><msub><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msub></math>&nbsp;, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of <span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <msub> <mrow> <mrow> <mi>M</mi> </mrow> </mrow> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> </msub> </mrow> </mrow> <mrow> <mrow> <msub> <mrow> <mrow> <mi>M</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> </mrow> </mrow> </mfrac> </math> </span><math><mfrac><mrow><mrow><msub><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msub></mrow></mrow><mrow><mrow><msub><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msub></mrow></mrow></mfrac></math>&nbsp;is:</strong></p> <div class="photo-widget-full"> <div class="figure"><picture><source srcset="" media="(max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1755770888phpBsHxa0.jpeg" alt="" width="239" height="178" loading="lazy"></picture></div> </div> <p>&nbsp;</p>

1 Views|Posted a year ago
Asked by Raj Pandey
New answer posted•a year ago
S
a year ago

90.5 J

- G M e M R + 1 2 M u 2 = - G M e M 2 R + 1 2 M v 2

  v = u 2 - G M e R Transverse velocity of rocket

V T →  Radial velocity of rocket

V R →

V - G M e 2 R

Kinetic energy M 10 V T = 9 M 10 G M e 2 R ; M 10 V r = M u 2 - G M e R

= 1 2 M 10 V T 2 + V r 2 = M 20 81 G M e 2 R + 100 u 2 - 100 G M e R

= M 20 100 u 2 - 119 G M 2 R

 

 

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

T² = (4π²r³)/GM
⇒ M = (4π²r³)/ (G T²)
⇒ M = 6 × 10¹¹ × (9 × 10? )³ / (450 × 60)²
= 6.48 x 10²³ kg
(Note: There is a calculation error in the source image. Using the formula and given values: M = (6e11 * (9e6)^3) / (27000)^2 = 6e23 kg)

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