Physics Gravitation

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New answer posted•a year ago
S
a year ago

m ω 2 . 2 d 3 = G . m . 2 m d 2 ⇒ ω = 3 G m d 3

T = 2 π ω = 2 π d 3 3 G m

 

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New answer posted•a year ago
S
a year ago

F 1 c o s 4 5 ° + F 2 c o s 4 5 ° + F 3 = m v 2 r

⇒ G m 2 ( 2 r ) 2 . 1 2 + G m 2 ( 2 r ) 2 . 1 2 + G m 2 ( 2 r ) 2 = m v 2 r  

  ⇒ v = G m 4 r ( 2 2 + 1 )            

Putting m = 1 kg and r = 1 m,

v = 1 2 G ( 1 + 2 2 )            

 

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Let the gravitational field is zero at a distance x from the mass m.

G m x 2 = G 9 m ( R - x ) 2

⇒ R - x = 3 x or x = R 4

Gravitational potential at R 4

= - G m R 4 - G 9 m 3 R 4

= - 4 G m R - 12 G m R

= - 16 G m R

...Read more

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New answer posted•a year ago
S
a year ago

V = (   no. of moles   ) ( 22.4   litre   ) =   mass     molar mass   22.4 * 10 - 3 m 3 = 4.5 * 10 3 18 * 22.4 * 10 - 3 m 3 = 5.6 m 3

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New answer posted•a year ago
S
a year ago

v e = 2 G M R = 2 G R × 4 3 π R 3 ρ

= 8 π G ρ 3 R 2

⇒ v e ∝ R

⇒ v e v = 4 R R ⇒ v e = 4 v

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