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New answer posted
a year agoContributor-Level 10
I = P/ (4πr²) . (i)
and I = (1/2)ε? E? ²c . (ii)
From (i) and (ii)
P/ (4πr²) = (1/2)ε? E? ²c
E? = √ (2P/ (4πε? r²c) ; E? = √ (9*10? *2*15)/ (15*15*10? *3*10? ) = 2*10? ³ V/m
New answer posted
a year ago
Contributor-Level 10
R? = (ρ? L)/a² R? = (ρ? L)/ (3a²)
Both are in parallel . R? = (R? )/ (R? +R? ) = (ρ? ρ? L)/ (a² (3ρ? +ρ? )
New answer posted
a year agoContributor-Level 10
µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
m (t) = A? sin ω? t {ω? = 2π*10? }
c (t) = A? sin ω? t {ω? = 2π*10*10³}
C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t
New answer posted
a year agoContributor-Level 10
(hc/λ) = 13.6Z² (1/1² - 1/4²) = 13.6Z² (3/4) ; [λ = (4/3)k]
β line of Paschen
(hc/λ') = 13.6Z² (1/9 - 1/25)
λ = k * (9*25/16) ; λ' = (3/4)λ * (9*25/16) = (3³*5²/2? )λ
New answer posted
a year agoContributor-Level 10
Applying conservation of momentum, m (ui + 2uj) + 3m (0) = 4m (vi +vj)
⇒ v = u / 4 and v' = u / 2
New answer posted
a year agoContributor-Level 10
F = ηAdv / dx
η = F (dx/dv) (1/A) = m * a * time * (1/area) = MV/A
New answer posted
a year agoContributor-Level 10
Note : As the incident light is unpolarized, intensity of emerging light does not depend on the polarization axis of polarizer.
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