Physics

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New answer posted

7 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Given, L = 2H

l = 2 sin (t2)

u = 0 2 L i d i = L 2 [ i 2 ] 0 2 = L 2 [ 4 0 ]

u = 2 2 * 4 = 4 J

New answer posted

7 months ago

0 Follower 2 Views

A
Aadit Singh Uppal

Contributor-Level 10

Power calculations can also differ based on the nature of forces, which are as follows:

  • Conservative Forces: Here, work done is path-independent. e.g., gravity, spring force
  • Non-Conservative Forces: Work depends on the path. e.g., friction

New answer posted

7 months ago

0 Follower 54 Views

R
Raj Pandey

Contributor-Level 9

R e q = 2 . 5 Ω

l = v R e q = 5 2 . 5 = 2 A

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

l 1 = 1 2 m r 2

l 2 = 1 2 m r 2 l 3 = 1 2 m r 2 l 4 = 2 5 m r 2

New question posted

7 months ago

0 Follower 2 Views

New answer posted

7 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

H = I 2 R t = 2 2 * R * 1 5

3 0 0 = 6 0 R

R = 5 Ω

Now for 3A, time = 10 sec

H ' = l 2 R t = 3 2 * 5 * 1 0 = 4 5 0 J

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

m ω 2 . 2 d 3 = G . m . 2 m d 2 ω = 3 G m d 3

T = 2 π ω = 2 π d 3 3 G m

 

New answer posted

7 months ago

0 Follower 8 Views

R
Raj Pandey

Contributor-Level 9

ceq = 2 4 * 8 3 2 = 6 μ F

 

 

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

α = Δ l C Δ l E = 3 . 5 4 = 7 8

β = α 1 α = 7 / 8 1 7 / 8 = 7

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Focus of a spherical convex mirror is in the same side of centre of curvature. Thus, f = + 1 2 r .

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