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New answer posted

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Least count = Pitch / (Total divisions on circular scale)
In 5 revolution, distance travelled = 5mm
? In 1 revolution, distance travelled = 1mm
So least count = 1/50 = 0.02mm = 0.002 cm
So, Assertion is not correct but reason is correct

New answer posted

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

r? = 10αt²î + 5β (t-5)?
v? = dr? /dt = 20αtî + 5β?
As L? = m (r? * v? )
So, at t=0, L=0
given L is same at t=t as at t=0
⇒ r? * v? = 0
⇒ (10αt²î + 5β (t-5)? ) * (20αtî + 5β? ) = 0
⇒ 50αβt² (î*? ) + 100αβt (t-5) (? *î) = 0
⇒ 50αβt² k? - 100αβt (t-5) k? = 0
⇒ 50t² - 100t (t-5) = 0
⇒ 50t² - 100t² + 500t = 0
⇒ -50t² + 500t = 0
⇒ 50t (10 - t) = 0
⇒ t = 10 second

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

f = (N? - N? (e? )/N?
f = 1 - e?
df/dt = 0 - e? * -λ = λe?

New answer posted

5 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

A→B & D→C (isothermal process)
So, TA = TB & TD = TC. Now B→C & D→A (adiabatic process)
|WBC| = nR/ (γ-1) (TB - TC)
|WAD| = nR/ (γ-1) (TA - TD) = nR/ (γ-1) (TB - TC)
∴ |WBC| = |WAD|

New answer posted

5 months ago

0 Follower 92 Views

V
Vishal Baghel

Contributor-Level 10

1 litre, T = 300K, P = 2 atm, KE = 2*10? J/molecule, no of molecule =?
No. of molecules = (no of moles) * NA = nNA
Also, n = PV/RT = PV/ (NAkT)
KE = (3/2)kT = 2*10? J [Given]
kT = (4/3)*10?
P = 2 atm = 2 * 1.013 * 10? N/m²
vol = 1 lit = 10? ³ m³
No. of molecules = PV/kT = (2*1.013*10? * 10? ³)/ (4/3)*10? ) ≈ 1.5 * 10¹¹

New answer posted

5 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

The circuit shown is an or GATE implemented using NAND gates.
Y = A + B

 

New answer posted

5 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

Polygon law is applicable in both the situation given but the equation given in the reason is not useful in explaining the assertion.

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

v = 1/√με = 1/√ (µ? µ? ε? ε? ) = c/√ (µ? ε? )
v = 3*10? / √ (1*81)
v = 3*10? / 9 m/s
= 0.33 * 10? m/s
= 3.33 * 10? m/s

New answer posted

5 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

v = √2gh velocity of efflux.
F = v ( dm/dt ) = v (aρv) = aρv² = 2aρgh
fr = µR = µAhρg
For just sliding, for = F
µAhρg = 2aρgh
or µ = 2a/A

New answer posted

5 months ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

MV? = 3MV? = p
λ = h/mv = h/p
λ? /λ? = 1

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