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8 months ago

Physics Class 11th

A boy pushes a box of mass 2kg with a force $\vec{F} = (20 \hat{i} + 10 \hat{j}) N$ on a frictionless surface. If the box was initially at rest, then-------------m is displacement along the x – axis after 10s.

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Payal Gupta

Contributor-Level 10

$a_{x} = \frac{F_{x}}{m} = \frac{20}{2} = 10 m / s^{2}$

$S_{x} = \frac{1}{2} a_{x} t^{2} = \frac{1}{2} * 10 * 1 0^{2}$

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8 months ago

Physics Class 12th

The maximum and minimum amplitude of an amplitude modulated wave is 16V and 8V respectively. The modulation index for this amplitude wave x * 10^-2. The value of x is----------.

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Payal Gupta

Contributor-Level 10

Modulation Index $(μ) = \frac{A_{m a x} - A_{m i n}}{A_{m a x} + A_{m i n}} = \frac{16 - 8}{16 + 8} = \frac{1}{3} = 0.33 = 33 * 1 0^{- 2}$

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8 months ago

Physics Laws of Motion

Two masses A and B, each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in figure. If the mass A starts moving away from mass B with acceleration 'a', then the acceleration of mass B will be:

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Vishal Baghel

Contributor-Level 10

Let the spring is in extension state and $a_{B} > a_{A}, {\vec{a}}_{A B} = - a_{A} \hat{i} - (- a_{B} \hat{i}) = (- a_{A} + a_{B}) \hat{i}$ $_{}_{}_{}_{}_{}_{}_{}$

Hence we can say that block moves away from block B in the frame of B

F – kx = MaB . (1)

kx = Ma. (2)

$\Rightarrow a_{B} = \frac{F}{M} - a$

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8 months ago

Physics Class 12th

In an electrical circuit, a battery is connected to pass 20 C of charge through it in a certain given time. The potential difference between two plates of the battery is maintained at 15V. The work done by the battery is--------- J.

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Payal Gupta

Contributor-Level 10

$W = q Δ V = 20 * 15 = 300 J$

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8 months ago

Physics Class 12th

The circuit contains two diodes each with a forward resistance of 50 $Ω$ and with infinite reverse resistance. If the battery voltage is 6 V, the current through the 120 $Ω$ resistance is---------mA.

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Payal Gupta

Contributor-Level 10

D₁ is forward biased & D₂is reverse biased.

$l = \frac{6}{120 + 130 + 50} = \frac{6}{300} = 2 * 1 0^{- 2} A = 20 * 1 0^{- 3} A = 20 m A$

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8 months ago

Physics Class 12th

The incident ray, reflected ray and the outward drawn normal are denoted by the unit vectors $\vec{a}, \vec{b} a n d \vec{c}$ respectively. Then choose the correct relation for these vectors.

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Vishal Baghel

Contributor-Level 10

$\hat{r} - \hat{i} = 2 c o s θ \hat{n} . . . . . . (1)$

$\hat{i} . \hat{n} = - c o s θ . . . . . . (2)$

$\Rightarrow \hat{r} = \hat{i} - 2 (\hat{i} . \hat{n}) \hat{n}$

$\Rightarrow \vec{b} = \vec{a} - 2 (\vec{a} . \vec{c}) \vec{c}$

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8 months ago

Physics Physics Thermodynamics

A container is divided into two chambers by a partition. The volume of first chamber is 4.5 litre and second chamber is 5.5 litre. The first chamber contain 3.0 moles of gas at pressure 2.0 atm and second chamber contains 4.0 moles of gas at pressure 3.0 atm. After the partition is removed and the mixture attains equilibrium, then, the common equilibrium pressure existing in the mixture is x * 10^-1 atm. Value of x is----------.

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Payal Gupta

Contributor-Level 10

$P = \frac{P_{1} V_{1} + P_{2} V_{2}}{V_{1} + V_{2}} = \frac{2 * 4.5 + 3 * 5.5}{10} = \frac{9 + 16.5}{10} = 25.5 * 1 0^{- 1} a t m$

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8 months ago

Physics Physics Wave Optics

In a Young's double slit experiment two slits are separated by 2mm and the screen is placed one meter away. When a light of wavelength 500nm used, the fringe separation will be

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Payal Gupta

Contributor-Level 10

$β = \frac{λ D}{d} = \frac{500 * 1 0^{- 9} * 1}{2 * 1 0^{- 3}} = 250 * 1 0^{- 6} m = 250 * 1 0^{- 3} m m = 0.25 m m$

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8 months ago

Physics Electric Charges and Fields

An inclined plane making an angle of 30° with the horizontal is placed in a uniform horizontal electric field $200 \frac{N}{C}$ as shown in the figure. A body of mass 1kg and charge 5 mC is allowed to slide down from rest at a height of 1m. If the coefficient of friction is 0.2, find the time taken by the body to reach the bottom.

$[g = 9.8 m / s^{2}; s i n 30 ° = \frac{1}{2}; c o s 30 ° = \frac{\sqrt[]{3}}{2}]$

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Vishal Baghel

Contributor-Level 10

$N = m g c o s 30 ° + q E s i n 30 °$

$a = \frac{m g s i n θ - q E c o s θ - μ N}{m} = 2.30 m / s^{2}$

$S = u t + \frac{1}{2} a t^{2}$

$\Rightarrow t = \sqrt[]{\frac{2 l}{a}} = 1.31 s e c$

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8 months ago

Physics Physics Mechanical Properties of Solids

The normal density of a material its $ρ$ and its bulk modulus of elasticity is K. The magnitude of increase in density of material, when a pressure P is applied uniformly on all sides, will be

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Payal Gupta

Contributor-Level 10

From defined of bulk modulus

$K = - \frac{P}{(d V / V)} . . . . . . . (1)$

m = $ρ v = c o n s t a n t$

$ρ d V + V d ρ = 0$

$\frac{d V}{V} = - \frac{d ρ}{ρ} . . . . . . . . . (2)$

With the help of equations (1) and (2), we can write

$K = - \frac{P}{(- \frac{d ρ}{ρ})} = \frac{ρ P}{d ρ} \Rightarrow d ρ = \frac{ρ P}{K}$

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