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New answer posted

5 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

W = q Δ V = 2 0 * 1 5 = 3 0 0 J

New answer posted

5 months ago

0 Follower 12 Views

P
Payal Gupta

Contributor-Level 10

D1 is forward biased & D2 is reverse biased.

l=6120+130+50=6300=2*102A=20*103A=20mA

New answer posted

5 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

r ^ i ^ = 2 c o s θ n ^ . . . . . . ( 1 )

i ^ . n ^ = c o s θ . . . . . . ( 2 )

r ^ = i ^ 2 ( i ^ . n ^ ) n ^

b = a 2 ( a . c ) c

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

P = P 1 V 1 + P 2 V 2 V 1 + V 2 = 2 * 4 . 5 + 3 * 5 . 5 1 0 = 9 + 1 6 . 5 1 0 = 2 5 . 5 * 1 0 1 a t m

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

β = λ D d = 5 0 0 * 1 0 9 * 1 2 * 1 0 3 = 2 5 0 * 1 0 6 m = 2 5 0 * 1 0 3 m m = 0 . 2 5 m m

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

N = m g c o s 3 0 ° + q E s i n 3 0 °

a = m g s i n θ q E c o s θ μ N m = 2 . 3 0 m / s 2

S = u t + 1 2 a t 2

t = 2 l a = 1 . 3 1 s e c

New answer posted

5 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

From defined of bulk modulus

K=P (dV/V)....... (1)

m = ρv=constant

ρdV+Vdρ=0

dVV=dρρ......... (2)

With the help of equations (1) and (2), we can write

K=P (dρρ)=ρPdρdρ=ρPK

New answer posted

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Frequency increases on filing. So, initial frequency of A is 335 Hz.

f = 340 – 5 = 335 Hz

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Z = R 2 + ( X L X C ) 2

Z = ( 1 2 0 ) 2 + ( 1 0 1 0 0 ) 2 = 1 5 0 Ω

ω = 1 L C = 1 1 0 1 * 1 0 4 = 1 0 5

? ω = 2 π f

f = 1 0 3 2 π 1 0 = 5 0 H z

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

A = A 0 e λ t 1 [Radio active decay law]

A 5 = A 0 e λ ( t 2 t 1 )

l n 5 = λ ( t 2 t 1 )

A v e r a g e l i f e = 1 λ = ( t 2 t 1 ) l n 5

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