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New answer posted

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Time period of second pendulum is 2 seconds.                                                                                                                                                                          &nbs

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New answer posted

10 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

R i = ρ l A

R f = ρ ( 1 . 2 5 l ) ( A / 1 . 2 5 ) = ( 1 . 2 5 ) 2 * ρ l A

R f = 1 . 5 6 2 5 * R i

R f R l R l * 1 0 0 = 5 6 . 2 5 %

New answer posted

10 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

v=ωk=301=30m/s

v=TμT=μv2=0.135*103102* (30)2=12.15N=1215*102N

New question posted

10 months ago

0 Follower 3 Views

New answer posted

10 months ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

l=12cε0E02=η* (P4πr2) Here η is the efficiency

E0=ηP2πr2cε0=1.25100*10002*3.14*4*3*108*8.85*1012

E0=12.58*3.14*3*8.85*104=13.69Vm=136.9*101V/m

New answer posted

10 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

mg – N = ma

N = m (g – a) = 60 * (10 – 1.8) = 60 * 8.2 = 492 N

New answer posted

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Bv = B sin 60°

B v = 2 . 5 * 1 0 4 * 3 2

E m f = B v * v * l = 2 . 5 * 1 0 4 * 3 2 * 1 8 0 * 5 1 8 * 1 = 1 0 8 . 2 5 * 1 0 3 v o l t s

New answer posted

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

U = 3PV + 4

n C v T = 3 P V + 4

n * f R T 2 = 3 P V + 4

f = 6 + 8 P V

f > 6 p o l y a t o m i c

New answer posted

10 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

As we know that Q = ωLR

Q'Q=L'R'*RL= (L'L)* (RR')=2*2Q'=4Q=4*100=400

New answer posted

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

λ = c v = Q 3 W 2 = I 3 T 3 M 2 L 4 T 4 [ λ ] = [ M 2 L 4 T 7 l 3 ]                                                                             

 

 

 

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