Physics

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New answer posted

5 months ago

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S
Syed Aquib Ur Rahman

Contributor-Level 10

Resonance occurs when the frequency of an external periodic force matches the natural frequency of a system. From that, physicists know that resonance causes the amplitude of oscillations to increase significantly. This can be beneficial in devices, such as musical instruments, but dangerous in structures like bridges.

New answer posted

5 months ago

0 Follower 1 View

S
Syed Aquib Ur Rahman

Contributor-Level 10

The phase in SHM tells us the position and direction of motion of the particle at a specific instant. It determines the state of oscillation and includes both displacement and time information.

New answer posted

5 months ago

0 Follower 1 View

S
Syed Aquib Ur Rahman

Contributor-Level 10

The restoring force in SHM is the force that always acts towards the mean position and is directly proportional to the displacement from it. It follows F=? kx. Here, the negative sign indicates the force is in the opposite direction to the displacement.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

According to Brewster's law, reflected rays are completely polarized and refracted rays are partially polarized.

 

New answer posted

5 months ago

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alok kumar singh

Contributor-Level 10

Time period of Oscillation, T = 2 π I M B

1 4 = 2 π 9 . 8 * 1 0 6 M * 0 . 0 4 9

1 1 6 = 4 π 2 * 9 . 8 * 1 0 6 M * 4 9 * 1 0 3

M = 4 π 2 * 9 . 8 * 1 0 6 4 9 * 1 0 3 * 1 6

= 4 π 2 * 9 . 8 * 1 6 * 1 0 3 4 9

= 1 2 . 8 π 2 * 1 0 3 * 1 0 2 * 1 0 2

=1280π2*105Am2

New answer posted

5 months ago

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alok kumar singh

Contributor-Level 10

Sol. Before collision

It undergoes completely inelastic collision

Using conservation of linear momentum

Initial momentum = Final momentum

m v 1 = m v 2 + m v 2

m v 1 = 2 m v 2

v 1 v 2 = 2 1

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

The potential V at any point, at distance r from centre of dipole = KPcosθ r 2

At axial point where  θ=0? , V=KPr2=9*109*4*10622=9*103 V

At axial point where  θ=180? , V=KPr2=9*103 V

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

x = 2 t 1

v=dxdt=2 m s1

P = F · v

=2*5=10 W

New answer posted

5 months ago

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alok kumar singh

Contributor-Level 10

Given circuit is balanced Wheatstone bridge

C A B = 1 + 1

= 2 ? F

 

New answer posted

5 months ago

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alok kumar singh

Contributor-Level 10

In the case of pure rolling,

The topmost point will have velocity 2 v while point Q i.e. the lowest point will have zero velocity. Hence point P moves faster than point Q .

 

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