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New answer posted

7 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) density = mass/volume as density is same so volume is also same.

According to Stefan's law H AT4  where A is the area and T is the temperature

Hsphere:Hcube:Hplate= Asphere:Acube:Aplate

As Aplate is maximum.

Hence the plate will cool the fastest.

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer.   (a)

Explanation-The force between (q1, q2) and (q1, q3) is must be attractive to net forces act in positive direction of x . so q1 must be negative. But if we place a positive charge Q in positive direction of x then it must be attractive towards along x-axis. So it will be attractive towards positive x axis. 

New answer posted

7 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(d) Let radius of sphere be R . as the temperature increases radius of the sphere increases.

Original volume Vo= 4 3 π R 3

Coefficient linear expansion = α

Coefficient of volume expansion =3 α

d V V d T = 3 α  , dV= 4 π R3  α ? T =increase in volume

New answer posted

7 months ago

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation-The electric lines of forces always starts from a positive charge and   ends at a negative charge. In case of a single isolated charge, electric lines of force start from positive charge ends at infinity.

(i) Here, in the figure, the electric lines of force starts from A and C. Therefore, charges A and C must be positive.

(ii) The number of electric lines of forces starting from charge C are maximum, so C must have the largest magnitude.

(iii) From the figure we see that a neutral point exists between charges A and 

Here, more number of elect

...more

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7 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(a) We know that temperature increases vibrations of molecules about their mean position increases. Hence kinetic energy associated with random motion of molecules increases.

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7 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

As the temperature is increased length of the pendulum increases.

T=2 π L g

So if we increase L then T also increases.

New answer posted

7 months ago

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Answer = d 2 (1+ 3 ) towards left.

Explanation -lets consider 2q charge is placed in between q and -3q, here it will definitely experience some force q charge repel 2q charge and -3q charge will attract 2q charge. So 2q charge will move towards -3q charge.

Now lets consider it to the left of q at some distance x, here the force experience by q is repulsive and force experience by -3q is attractive . so they cancel out each other and no net force is experience by 2q.

Thus, force of attraction by -3q = force of repulsion by q

? k 2q q/x2 = k 2q 3q/ (x+d)2

 

? (x+d)2 = 3x

...more

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7 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(a) F= V ρ G

F ρ

F 4 0 C > F 0 0 C

Hence buoyancy will be less in water at 00C than that in water at 40C.

New answer posted

7 months ago

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- (i)The cesium atoms, are situated at the corners of a cube and Cl atom is situated at the centre of the cube. From the given figure, we can analyse that the chlorine atom is at equal distance from all the eight comers of cube where cesium atoms are placed. Thus, due to symmetry the electric field due to all Cs atoms, on Cl atom will cancel out. Hence net electric field at the centre of cube is zero.

(ii) we know, f=qE  E= Kq/r2= Ke/r2

F= e (E)=e (ke/r2)=ke2/r2

Distance= r 2 + r 2 + r 2 = 0.2 2 + 0.2 2 + 0.2 2 * 10-9m

F=8.99 * 109 (1.6 * 10-16)2/ (0.346 * 10-9)2=1.92 * 10-9N

New answer posted

7 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(b) Lowest point for scale A is 300 and lowest point for scale B is 00. Highest point for the scale A is 1800 and for scale B is 1000

t A - L E P A U F P A - L F P A = t B - L F P B U F P B - L F P B
t A - 30 180 - 30 = t B - 0 100 - 0

t A - 30 150 = t B 100 ,LFP= lower fixed point , UFP= upper fixed point ρ

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