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New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- a, b, c
Explanation- the positive charge Q is uniformly distributed at the outer surface of the enclosed sphere thus electric field inside the sphere is zero. So the effect of electric field on charge q due to positive charge Q is zero.
Now the only attractive and repulsive force between Q and q
Case 1 q>0 this creates repulsive force
Case 2 q<0 this creates attractive force
If q is shifted from the centre then the positive charges nearer to this charge will attract it towards itself and charge q will never return to its centre.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (a), (b), (c), (d)
Explanation- The positive charge Q is uniformly distributed along the circular ring then electric field at the centre of ring will be zero, hence no force is experienced by the charge if it is placed at the centre of the ring.
Now the charge is displaced away from the centre in the plane of the ring. There will be net electric field opposite to displacement will push back the charge towards the centre of the ring if the charge is positive. If charge is negative, it will experience net force in the direction of displacement and the charge w
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer – (a, c)
Explanation- Gauss's law states that the total electric flux of an enclosed surface is given by q/? 0, where q is the charge enclosed by the surface.
So total charge inside the surface is = Q-2Q = -Q
Therefore total flux through the surface of the sphere = -Q/? 0
Now, charge 5Q is lies outside the surface, thus it makes no contribution to electric flux through the given surface. So both option a and c are true.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (c), (d)
Explanation- electric field is not necessarily zero may it become zero by their algeabric sum. For dipole the electric field is always ∝ 1/r3 and it is also conservative.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (b), (d)
Explanation- if we place a charge then we must experience some forces but if there would be no charge so field is continuous
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (c), (d)
Explanation- It is only possible when charges must be outside the surface or field line entering or leaving the surface are equal.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (a)
Explanation- field lines are always perpendicular to the surface.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (a)
Explanation- when a point positive charge brought near an isolated conducting plane, some negative charge develops on the surface of the plane towards the charge and an equal positive charge develops on opposite side of the plane. By process called induction.
New answer posted
10 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(b), (c), (d) When the hot milk in the table is transferred to the surroundings by conduction, convection and radiation.
According to newton's law of cooling temperature of the milk falls of exponentially. Heat also will be transferred from surroundings to the milk but will be lesser than that of transferred from milk to surroundings. So option b, c, d satisfy.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (c)
Explanation- As the space is increasing towards right means electric field is decreasing so as force is also decreasing . so force on -p is more than the force on +p
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