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New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Vrms=
Vrms=
T1=27oC= 27+273=300K
T2=127oC= 127+273= 400K
Vrms2=
New answer posted
a year agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Explanation- according to the relation = also T
New answer posted
a year agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer – (a, d)
Explanation- potential drop across AB is independent to R' also when we decrease the value of R the current will also very large. According to the relation I=e/R+r
New answer posted
a year agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer – (b, d)
Explanation-Algebraic sum of the currents flowing towards any point in an electric network is zero. It also tell us about the conservation of charge.
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
V
V/T = constant
T1=273+27=300K
T2= 273+327= 600K
V1= 100cc
V2=V1 (600/300)
V2=2V1
V2= 2 (100)=200cc
New answer posted
a year agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (a)
Explanation- I=AneVd , current is directly proportional to drift velocity.
New question posted
a year agoNew answer posted
a year agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (a)
Explanation- R= for greater value of R, A should be less and its possible value when connected across 1cm 1/2cm faces.
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
molar mass = mass of avogadro's number of atoms= 6.023 atoms.
197 g of gold contains =6.023
1g of gold contain= atoms
39.4 g of gold atoms = atoms
New answer posted
a year agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (b)
Explanation-The potential drop along the wires of potentiometer should be greater than emfs of cells.
In a potentiometer experiment, the emf of a cell can be measured if the potential drop along the potentiometer wire is more than the emf of the cell to be determined. Here, values of emfs of two cells are given as 5 V and 10 V, therefore, the potential drop along the potentiometer wire must be more than 10 V.
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