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New answer posted

a year ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Vrms= 3 R T M

Vrms= T

V r m s 1 V r m s 2 = T 1 T 2

T1=27oC= 27+273=300K

T2=127oC= 127+273= 400K

100 V r m s 2 = 300 400 = 3 2

Vrms2= 2 * 100 3 = 200 3 m / s

New answer posted

a year ago

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Explanation- according to the relation ρ = mne2t also T ∝1t

New answer posted

a year ago

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer – (a, d)

Explanation- potential drop across AB is independent to R'  also when we decrease the value of R the current will  also very large. According to the relation I=e/R+r

New answer posted

a year ago

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer – (b, d)

Explanation-Algebraic sum of the currents flowing towards any point in an electric network is zero. It also tell us about the conservation of charge.

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a year ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

V ∝ T

V/T = constant

V 1 T 1 = V 2 T 2

T1=273+27=300K

T2= 273+327= 600K

V1= 100cc

V2=V1 (600/300)

V2=2V1

V2= 2 (100)=200cc

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (a)

Explanation- I=AneVd  , current is directly proportional to drift velocity.

New question posted

a year ago

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New answer posted

a year ago

0 Follower 13 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (a)

Explanation- R= δlA for greater value of R, A should be less and its possible value when connected across 1cm * 1/2cm faces.

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a year ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

molar mass = mass of avogadro's number of atoms= 6.023 * 10 23 atoms.

197 g of gold contains =6.023 * 10 23 a t o m s

1g of gold contain= 6.023 * 10 23 197 atoms

39.4 g of gold atoms = 6.023 * 10 23 * 39.4 197 = 1.2 * 10 23 atoms

New answer posted

a year ago

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (b)

Explanation-The potential drop along the wires of potentiometer should be greater than emfs of cells.
In a potentiometer experiment, the emf of a cell can be measured if the potential drop along the potentiometer wire is more than the emf of the cell to be determined. Here, values of emfs of two cells are given as 5 V and 10 V, therefore, the potential drop along the potentiometer wire must be more than 10 V.

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