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New answer posted
10 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(a), (d) During the process AB temperature of the system is 00C . hence it represents phase change that is transformation of ice into water while temperature remains 00C.
BC represents rise in temperature of water from 00C to 1000C. now water starts converting into steam which is represented by CD.
Which is only represents by a, d options
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (b)
Explanation-The charges may be located anywhere inside the surface, if the surface is so chosen that there are some charges inside and some outside, the electric field on the left side of equation is due to all charges, both inside and outside S.
New answer posted
10 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(b), (c) Smaller gulab jamun having least surface area hence they will be heated first. As in case of smaller gulab jamun heat radiates will be less.
Similarly smaller pizzas are heated before bigger ones because of smaller surface area.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (d)
Explanation- Total flux inside a conducting sphere is depend upon the algeabric sum of total charge inside that surface, which is same for all fig. As it does not depend upon shape of a body
New answer posted
10 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(b), (d) Tx=Ty when x and y are in thermal equilibrium.
Tx TZ when x and z are not in thermal equilibrium.
Ty TZ
Hence y and z are not In thermal equilibrium.
Given Tx Ty
And Tx TZ
We cannot say about equilibrium of y and z.
They may or may not in thermal equilibrium
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (a)

Explanation- when a positive point charge is brought near an isolated conducting sphere without touching the sphere, then the free electron in the sphere are attracted towards the positive charge. This leaves an excess positive charge on right side of sphere . And also by induction the negative charge is setup across left side. So field lines first goes from positive charge (+q) to negative charge of sphere then from positive charge of sphere to negative charge anywhere in the universe.
New answer posted
10 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(c) density = mass/volume as density is same so volume is also same.
According to Stefan's law H AT4 where A is the area and T is the temperature

Hsphere:Hcube:Hplate= Asphere:Acube:Aplate
As Aplate is maximum.
Hence the plate will cool the fastest.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer. (a)
Explanation-The force between (q1, q2) and (q1, q3) is must be attractive to net forces act in positive direction of x . so q1 must be negative. But if we place a positive charge Q in positive direction of x then it must be attractive towards along x-axis. So it will be attractive towards positive x axis.


New answer posted
10 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(d) Let radius of sphere be R . as the temperature increases radius of the sphere increases.
Original volume Vo= 3

Coefficient linear expansion =
Coefficient of volume expansion =3
3 , dV= 4 R3 =increase in volume
New answer posted
10 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
Explanation-The electric lines of forces always starts from a positive charge and ends at a negative charge. In case of a single isolated charge, electric lines of force start from positive charge ends at infinity.
(i) Here, in the figure, the electric lines of force starts from A and C. Therefore, charges A and C must be positive.
(ii) The number of electric lines of forces starting from charge C are maximum, so C must have the largest magnitude.
(iii) From the figure we see that a neutral point exists between charges A and
Here, more number of elect
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