Quantitative Aptitude Prep Tips for MBA

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New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

9B + 3 + 5G + 4 = 200  9B + 5G = 193

The positive integer solutions are (B, G) = (2, 35) (7, 25) (12, 17) (17, 8)

Only one of the (B, G) gives G > B and 9B + 3 > 100, i.e. (B, G) = (12, 17)

 

17 – 12 = 5

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

(c) :As per the problem:

Average score of 20 candidate = 25 marks

Total score of 20 candidate = 500 marks

Let the score of the topper be x. Then,

( 5 0 0 x ) 1 9 = 2 3

500 – x = 437

x = 500 – 437 = 63 marks

New answer posted

a month ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

9B + 3 + 5G + 4 = 200  9B + 5G = 193

The positive integer solutions are (B, G) = (2, 35) (7, 25) (12, 17) (17, 8)

Only one of the (B, G) gives G > B and 9B + 3 > 100, i.e. (B, G) = (12, 17)

 

12 * 9 – 17 * 5 = 23

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

f (3n) – f (3n– 3) = n

n = 1

f (3) – f (0) = 1

f (0) = 0

n = 2

f (6)f (3)=2? ? ? ?

f (3n) – f (3) = 2 + 3 + 4+…………….+ n

f (3n) = 1 + 2 + 3 +…………….+ n

n (n+1)2

?  f (1312) – f (3 * 311)

3112 (311+1)=322+3112

Hence, remainder  [322+311210] = 8

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

1log10105=13 [log1010x*51/32]

3 [log101010 – log10105] = log1010x*51/32

log101023 = log1010x*51/32

23 = x*51/32

x = 2451/3

Hence, m + 3n = 4+3*13 = 5

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

Let the interest rate be r percent interest earned from 1.2 Lacs at the end of year

= 1,200,000 * r /100

= 1200r

From 1.8 lakh, = 8/12 * 1, 80,000 * 2r/100

= 2400r

Total interest = 3600r = 54000

r = 15 percent

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

Let the quotient obtained when the numbers is divided by 3, 5 and 6 be x1, x2 and x3

Respectively

N = 3 x1 + 1

x1 = 5 x2 + 3

x2 = 6 x3 + 2

N = 3 [5 (6 x3 + 2) + 3] + 1

=90 x3 + 40 < 1000

x3 can take 11 values

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

Since the two train meet after one hour, their relative speed (sum of their speeds as they are travelling in opposite direction) is 138km/hr. The speed of faster train is asked; we know it has to be greater than 69km/hr. as B takes more time to cover the same distance.

Option (a) is correct.

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

Assuming that

b – c = p b = c + p

c – a = q c = a + q

Hence b = c + p

= a + q + p

?  y+1 (bc)a (ca) can be written as a + q + p + 1a.p.q

Apply AM GM in equally concept in above equation

a+q+p1a.p.q44a*p*q*1a.p.q

a+q+p1a.p.q41

a+q+p1a.p.q4

Hence, minimum value is 4

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

Let the price of 1 apple, 1 banana and 1 orange is a, b and c respectively.

3a + 5b + 3c = 85     equation 1

4a + 4b + 5c = 87     equation 2

5a + 3b + 7c =?

Multiply equation 1 and 2 by m and n respectively and adding will given the required equation

3m+5n = 7     equation 3

5m+4n = 3     equation 4

3m+4n = 5     equation 5

Equation 4 – equation 5

2m= –2

m= –1 and n = 2

Substituting these values in equation 3 which also satisfy

Equation 1 * (–1) + equation 2 *2

= 5a + 3b + 7c

= 85 (–1) + 87 (2)

5a + 3b + 7c = 89Rs.

Price of 5 apple,

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