Quantitative Aptitude Prep Tips for MBA

After x hours $\frac{x}{12}$ $\frac{}{}$ of the first candle is burnt out = $\frac{x}{8}$ $\frac{}{}$ of the second is burnt out.

Remaining parts are $\left(1-\frac{x}{12}\right)and\left(1-\frac{x}{8}\right)$ $$

$Now,\left(1-\frac{x}{12}\right)=2\left(1-\frac{x}{8}\right)orx=6hrs.$

(c) :As per the problem:

Initial amount of rum = 30 litres and water = 18 litres

New ratio of rum to water = 1 : 2

Therefore, if x is the amount of water to be added, then

$\frac{30}{(18+x)}=\frac{1}{2}$

18 + x = 60

x = 42 litres

(a): $Asgiven\frac{p-3}{q}=-1\Rightarrow p+q=3$ $$ . (1)

$$ $Also\frac{p}{q+2}=\frac{1}{4}\Rightarrow 4p-q=2$  . (2)

(c):Let X & Y be their ages at the time of marriage.

X – Y = 8. (1)

(X – 8) = 2 (Y – 8). (2)

Solve to get X = 24, Y = 16.

Let the solutions added be 2, 4 and 1 litre, respectively. Then quantity of ethanol in the solution is

$2*\frac{1}{3}+4*\frac{2}{5}+1*\frac{3}{7}$

$\begin{array}{l}=\frac{2}{3}+\frac{8}{5}+\frac{3}{7}\\ =\frac{70+168+45}{105}\\ =\frac{283}{105}\end{array}$

So, the quantity of methanol

$\begin{array}{l}=7-\frac{283}{105}\\ =\frac{735-283}{105}\\ =\frac{452}{105}\end{array}$

So the ratio of ethanol to methanol in the resultant solution is 283: 452.

(a):Two digit numbers where sum is 10 are 19, 28, 37, 46, 55, 64, 73, 82 and 91. Out of the given number only 37 + 36 = 73. 37 is the original number and 73 is the number obtained by reversing the digits.

Let us assume that each receives 100 when 21.

100 = P1 (1.0625)3 …. (1)

100 = P2 (1.0625)2 …. (2)

From (1) & (2), P1 : P2 = 16 : 17

Now A's share $=Rs.8448*\frac{16}{33}=Rs.4096$ $$

B's share = Rs. 4352

Now amount of A & B at 21 =

(4096) $$ ${\left(\frac{17}{16}\right)}^3=Rs.4913$ .

(c):x * y = 0.8x (y + 4) or y = 16 y + 4 = 20.

Old price = $\frac{}{}$ = $\frac{}{}$ = Rs. 0.625/sugar

New price = $\frac{}{}$ = Rs. 0.5/sugar

(d):The three different Maths books can be arranged in 3! ways. Now there are four places created for the Chemistry books such that they are not together.

The four Chemistry books can be arranged in the available four places in 4! ways.