Quantitative Aptitude Prep Tips for MBA

CP of 378 = SP of 525

$\begin{array}{l}\frac{378}{525}=\frac{SP}{CP}\\ \frac{SP}{CP}=0.72\end{array}$

So, 28% loss

$\frac{{(27+5)}^{332}}{9}=\frac{{(5)}^{332}}{9}=\frac{5^2\times {(125)}^{110}}{9}=25\times {(-1)}^{110}=7$

Let the speed of B = X kmph.

We have X * t = 240, (X – 15) * t = 180

or X = 60, X – 15 = 45

The work done by 12 boys in 20 days = $\frac{4}{7}$ $\frac{}{}$

So, remaining work need to be done in 6 days = $\frac{3}{7}$

$\frac{M_1*D_1}{W_1}=\frac{M_2*D_2}{W_2}$ $\frac{}{}$

$\frac{12*20}{\frac{4}{7}}=\frac{M_2*6}{\frac{3}{7}}$

We get, M2 = 30. Hence, 18 extra boys are required.

LCM of 70, 84, 280 is 840.

Let total work = 840 units.

Per hour work of P = $\frac{840}{70}=12\text{?}units/hour$ $$

Per hour work of Q = $\frac{840}{84}=10\text{?}units/hour$ $$

Per hour work of R = $\frac{840}{280}=3\text{?}units/hour$ $$

Number of hours they require together =

$\frac{}{}$ $\frac{840}{12+10+3}=\frac{840}{25}$  = 33 hours and 36 minutes

Five years ago the ratio of their ages was 5:3 with the total age being 64 years. Their individual ages will be 40 and 24 years.

Today their ages will be 45 years and 29 years and after 9 years their ages will be 54 and 38 years.

Required ratio will be 27 : 19.

612 = 212 * 312. For perfect cubes, power must be multiple of 3.

Therefore, power of 2 equal 20, 23, 26, 29, 212 and power of 3 equals 30, 33, 36, 39, 312 So, number of divisors equal 5* 5 = 25.

New rent = 2730 per month.  Rs. 2720 * 12 = Rs. 32640 per year

Net for X = 70 * 4 + 50 * 3 + 66 * 5 = 760

For Y = 50 * 4 + 70 * 8 = 760

For Z = 40 * 7 + 24 * 5 = 400

The shares will 12920, 12920 and 6800.

When T2 is at 45 points, T3 is at 40 points, that is, T2 can beat T3 by 5 points in a 45 point game. In a 765 point game, T2 can beat T3 by $\frac{765}{45}*5$ $\frac{}{}$ = 85 points.