Quantitative Aptitude Prep Tips for MBA

(c): A + B + C = 12540 .… (1)

$A=\frac{3}{7}(B+C)$

$\frac{A}{B+C}=\frac{3}{7}$

So, A’s Share = $\frac{3}{10}\times 12540=3762$ $\frac{}{}$

$B=\frac{2}{9}(A+C)$

$\frac{B}{A+C}=\frac{2}{9}$

So, B’s Share = $\frac{2}{11}\times 12540=2280$

(c):Let x be the percentage of water in the resultant mixture.

Using the alligation rule, we have

$\frac{30}{25}=\frac{(40-x)}{(x-20)}$

6 (x – 20) = 5 (40 – x)

6x – 120 = 200 – 5x

11x = 320

x = $\frac{320}{11}=29.09\mathrm{\%}$

(b):Vande Bharat takes 6 hours from New Delhi to Bhopal. Duronto takes 4 hours from Bhopal to New Delhi. Let the distance between Delhi and Bhopal be ‘d’ kms.

Speed of Vande Bharat = $\frac{d}{6}km/hr$ $$

Speed of Duronto = $\frac{d}{4}km/hr$ $$

They will meet after = $\frac{d}{\frac{d}{6}+\frac{d}{4}}=2\frac{2}{5}hours$ $$

= 2 hours & 24 minutes

Hence, required time = (7 + 2.24)

= 9 : 24 a.m.

Factorised from = 2⁴ × 3⁴ × 5² × 7²

Total no. of factor = 5× 5 × 3 × 5

= 225 factors

113^rd factor = $\sqrt[]{N}$

 i.e. 7 × 5 × 3² × 2² = 1260

150/- wax; 8.5/- thread; 12.5/- coloured paper; 9/- silver powder

Profit = 40%.

Net input = 150 + 8.5 + 12.5 + 9 = 180/-

Net profit = 180 * .4 = 72/-

$$ $\frac{1}{2}$  the candles = $\frac{}{}$ $\frac{1}{2}$   (180) = 90/-

At 50% profit = 45.

90 + 45 = 135/-

Let the remaining $\frac{1}{2}$ $\frac{}{}$ = x

Net price = (72 + 180) = 135 + x

x = 117

Pro

P (1.05)2 − P = 369 or P = 3600

$\frac{x}{5}+\frac{x}{6}$ = CP (x oranges of each type) = $\frac{11x}{30}$  and SP =  $\frac{2x}{7}$

On selling 2x oranges, loss = $\frac{x}{5}+\frac{x}{6}-\frac{2x}{7}=\frac{17x}{210}$

If loss is 34, Total oranges =  $\frac{2x\times 34}{\left(\frac{17x}{210}\right)}=840$

(c):Double in 4 years, four times in 8 years, eight times in 12 years.

(b):Notice that the difference between the divisors and the remainder is constant. Therefore take the LCM of the divisors or any multiple of the LCM and subtract.

The difference between the divisor and the remainder

which is 2 in this case.

Therefore, the smallest 3 digit number

= 15 * 7? 2 = 105 – 2