Quantitative Aptitude Prep Tips for MBA

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

(c) :As per the problem:

Average score of 20 candidate = 25 marks

Total score of 20 candidate = 500 marks

Let the score of the topper be x. Then,

( 5 0 0     −     x ) 1 9     =     2 3

500 – x = 437

x = 500 – 437 = 63 marks

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

f (3n) – f (3n– 3) = n

n = 1

f (3) – f (0) = 1

f (0) = 0

n = 2

f (6)–f (3)=2        ?                ? ?           ?

f (3n) – f (3) = 2 + 3 + 4+…………….+ n

f (3n) = 1 + 2 + 3 +…………….+ n

= n (n+1)2

?  f (1312) – f (3 × 311)

3112 (311+1)=322+3112

Hence, remainder  [322+311210] = 8

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New answer posted•a year ago
S
a year ago

1−log10105=13 [log1010x×51/32]

3 [log101010 – log10105] = log1010x×51/32

log101023 = log1010x×51/32

23 = x×51/32

x = 2451/3

Hence, m + 3n = 4+3×13 = 5

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New answer posted•a year ago
S
a year ago

Let the interest rate be r percent interest earned from 1.2 Lacs at the end of year

= 1,200,000 * r /100

= 1200r

From 1.8 lakh, = 8/12 * 1, 80,000 * 2r/100

= 2400r

Total interest = 3600r = 54000

r = 15 percent

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New answer posted•a year ago
S
a year ago

Let the quotient obtained when the numbers is divided by 3, 5 and 6 be x1, x2 and x3

Respectively

N = 3 x1 + 1

x1 = 5 x2 + 3

x2 = 6 x3 + 2

N = 3 [5 (6 x3 + 2) + 3] + 1

=90 x3 + 40 < 1000

x3 can take 11 values

...Read more

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New answer posted•a year ago
S
a year ago

Assuming that

b – c = p b = c + p

c – a = q c = a + q

Hence b = c + p

= a + q + p

?  y+1 (b−c)a (c−a) can be written as a + q + p + 1a.p.q

Apply AM GM in equally concept in above equation

a+q+p1a.p.q4≥4a×p×q×1a.p.q

a+q+p1a.p.q4≥1

a+q+p1a.p.q≥4

Hence, minimum value is 4

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New answer posted•a year ago
S
a year ago

Let the price of 1 apple, 1 banana and 1 orange is a, b and c respectively.

3a + 5b + 3c = 85     equation 1

4a + 4b + 5c = 87     equation 2

5a + 3b + 7c =?

Multiply equation 1 and 2 by m and n respectively and adding will given the required equation

3m+5n =

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New answer posted•a year ago
S
a year ago

Let the distance between Delhi (D) and Jaipur (J) be 8x and Akbar’s initial speed be 4a and final speed be 7a.

Let the point where he increased his speed at P and let Q be the point on DJ such that DP=58 (DJ)

PQPJ=47

Let PQ = 4y,

PJ = 7y

QJ = 7y – 4y = 3x

3y = 3x

y= x

PQ = 4x and PJ =7x

Required ratio = DPDJ

= x8x&nb

...Read more

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