Quantitative Aptitude Prep Tips for MBA
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Mann travelled one third of a Journey at 10 kmph, the next one third at 9 km/h & the rest at 8 kmph. If Mann had travelled half the journey at 10 kmph & the other half at 8 kmph, Mann would have taken half a minute more. Find the distance travelled by Mann.
Mann travelled one third of a Journey at 10 kmph, the next one third at 9 km/h & the rest at 8 kmph. If Mann had travelled half the journey at 10 kmph & the other half at 8 kmph, Mann would have taken half a minute more. Find the distance travelled by Mann.
(b):If X be the distance, we have:
or
X = 27 km.
A man used to save 15% of his income. His income is now 20% higher and his expenditure 10% higher. What percentage of his income does he now save?
A man used to save 15% of his income. His income is now 20% higher and his expenditure 10% higher. What percentage of his income does he now save?
(a):Let us suppose the income of man = Rs. 1000
Savings = 15% of 1000 = Rs. 150
Expenditure = 1000 – 150 = 850
New Income = 1.2 * 1000 = 1200
New Expenditure = 1.1 * 850 = 935
New Savings = 1200 – 935 = 265
Required percentage =
In how many ways can 756 be written as product two factors?
In how many ways can 756 be written as product two factors?
(c):Total number of factors of factors of 756 = 22 × 33 × 7 = (2 + 1) (3 + 1) (1 + 1) = 24
So, total sets are
The price of a table which is sold for Rs. 4000 is made up as follows: cost of material, 30%; cost of manufacture, 50%, profit, 20%. If the cost of material falls and the cost of manufacture rises 20%. Find the new profit if the table is still sold for Rs. 4000?
The price of a table which is sold for Rs. 4000 is made up as follows: cost of material, 30%; cost of manufacture, 50%, profit, 20%. If the cost of material falls and the cost of manufacture rises 20%. Find the new profit if the table is still sold for Rs. 4000?
(a):Cost of material = 30% of 4000 = 1200
New cost of material = = 1150
Cost of manufacturing = = 2400
So, new profit = 4000 – (2400 + 1150) = 450
What will be the last non zero digit of the [removed]1040)723 ?
What will be the last non zero digit of the [removed]1040)723 ?
(b):We have to find last non zero digit by 4 so we will eliminate 0 in question so now it becomes 104723 = 4 as 4odd = 4
If A gives B Rs. 20, A has 40% of what B has and B gives Rs. 40 to A, B will have 40% of what A has, then what is the amount originally A has?
If A gives B Rs. 20, A has 40% of what B has and B gives Rs. 40 to A, B will have 40% of what A has, then what is the amount originally A has?
(a):We have (A ¬ 20) = 0.4 (B + 20), i.e. A – 0.4B = 28
And (B – 40) = 0.4 (A + 40), i.e. B – 0.4A = 56
Solve these equation's we get A = 60 Rs.
A salesman charges Rs. 240 during a normal 40-hour week. During a sale, his rates are increased by 50%. What is his commission if he puts in 60 hours during the sale?
A salesman charges Rs. 240 during a normal 40-hour week. During a sale, his rates are increased by 50%. What is his commission if he puts in 60 hours during the sale?
(b):In normal time rate = Rs. 6 per hour
During sale rates are increased by 50% i.e.,
Rate 40-hour week = 240 + 50% of 240 = Rs. 360
Rate per hour = Rs. 9 per hour
Now, according to the question,
Required commission = 9 * 60 = Rs. 540
Find the digit sum of 1! + 2! + 3! + 4! + 5! + …. + 500!
Find the digit sum of 1! + 2! + 3! + 4! + 5! + …. + 500!
(c):The digit sum of factorial of numbers till 5! is 9. 6! onwards each factorial will have digit sum as 9
If the selling price of an item is Rs. 360 and the profit is 25%, find the profit or loss if the same item is instead sold for Rs 260?
If the selling price of an item is Rs. 360 and the profit is 25%, find the profit or loss if the same item is instead sold for Rs 260?
(a):From the problem, we have
CP
CP = 72 * 4 = Rs.288
If the same item is sold for Rs.260, there will be a loss of Rs. 288 – Rs. 260 = Rs. 28
The average weight of a body, as calculated by the average of seven different experiments is 53.735 gms, while the average of first three is 54.005 gms, the fourth was greater than the fifth by 0.004 gms, while the average of sixth and seventh was 0.01 gms less than the average of the first three. Find weight of the body as obtained by the fourth experiment.
The average weight of a body, as calculated by the average of seven different experiments is 53.735 gms, while the average of first three is 54.005 gms, the fourth was greater than the fifth by 0.004 gms, while the average of sixth and seventh was 0.01 gms less than the average of the first three. Find weight of the body as obtained by the fourth experiment.
Let weight of body by fourth experiment = x
Net total of seven experiments = 53.735 * 7
= 376.145 gms.
Net total of first three = 3 * 54.005 = 162.015 gms.
Net total of 6th & 7th = 2 * 53.991 = 107.982 gms.
W5 + W4 = (x + 0.004) + x = 2x + 0.004
162.015 + 2x + 0.004 + 107.982 = 376.145
x = 53.072 gms