Quantitative Aptitude Prep Tips for MBA

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

Find the greatest number of six digits which, when divided by 6, 7, 8, 9 & 10, gives 4, 5, 6, 7 & 8 respectively as remainders.

1 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

Option (b) and (c) both satisfies the given condition, but 997918 is the larger of the two.

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

If x + $\frac{1}{x}$ = y, then for x > 0

4 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

Since x > 0 then at x = 1, we get y = 2 and for the rest values we get y > 2

Also for 0 < x < 1 ; x+ $\frac{1}{x}$ > 2

and for x > 1 ; x+ $\frac{1}{x}$ > 2

Hence, y ≥ 2

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

The diagonal of a square is $4 \sqrt[]{2}$ cm. The diagonal of another square whose area is double that of the first square is

8 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

We know that,

$a^{2} + a^{2} = {(4 \sqrt[]{2})}^{2}, a^{2} = 16, a = 4$

Now, 2 (area of square) = (square of diagonal)

So, for new area 32 (16 × 2)

2 × 32 = d²

8 = d

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

Three persons P, Q, R finished a piece of work. P worked at it for 5 days, Q for 7 days and R for 9 days. Their daily wages were in the ratio of 4 : 3 : 2 and they earned a total of Rs. 5900. What were the daily wages of P?

4 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

Final ratio of wages = 5 × 4 : 7 × 3 : 9 × 2 = 20 : 21 : 18

Total wages received by P = $\frac{20}{59} \times 5900 = 2000$

Daily wage of P = $\frac{2000}{5} = 400$

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

A cylindrical container has its height twice the radius of the base. If due to imperfection in measuring callipers, 1 cm is taken as 1.02 cm, the percentage error in the volume is

5 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

Let h = height of the container,

Given, h = 2r

$∴$ Volume v = πr²h = πr² (2r) = 2πr³

$∴$ Absolute error = (1.02)³ × 2πr³ − 2πr³ × 13

= 2πr³ [ (1.02)² − 1] = 2πr³ [1.0612 − 1]

= 0.0612 × 2πr³

$∴$ % error $= \frac{0.0612 \times 2 π r^{3}}{2 π r^{3}} \times 100 % = 6.12 %$

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

If $\sqrt[]{a^{b}} = 5 b + a^{2}$ then (a, b) could be

5 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

Put a = 2, b = 12 in $\sqrt[]{a^{b}} = 5 b + a^{2}$

$∴ \sqrt[]{2^{12}} = 5 \times 12 + 4 = 64$

$\Rightarrow$ 26 = 64, which is true.

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

P1 was a very lazy person. When he went for hunting a job, everyone refused to engage him, except farmer P2. P2 engaged P1 at a wage of Rs. 300 per day for a month of 28 days. However, he set a condition that P1 would forfeit Rs. 100 each day if he idled. P1 accepted the job. At the end of the month, it was found that neither owed the other anything. How many days did P1 work in that month?

3 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

For every day's work, P1 can afford to miss 3 days.

Hence, to break even it has to be 7 days' work in 28 days.

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

If a bus increase its usual speed by 7 km/hr, then it can travel distance AB in one hour less then the usual time. If the bus decreases its usual speed by 5 km/hr, then it can travel distance AB in 2 hours more than the usual time. What is the distance AB?

5 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

Let Ab = X km and speed of bus be Y km/hr and time be T hrs original equation becomes $\frac{X}{Y} = T . . . . . (1)$

By increasing speed by 7 km/hr equation becomes

$\frac{X}{y + 7} = T - 1 . . . . . (2)$

By decreasing speed by 5 km/hr equation becomes

$\frac{X}{y - 5} = T + 2 . . . . . (3)$

On solving equation 1, 2 & 3 we get the value of y as and

$\frac{35}{3}$ and $T = \frac{8}{3}$

$∴$ AB = X = $\frac{280}{9}$

≈ 31 km

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

**Given A + 4 = B + 5 = C + 6 = D + 7 = A + B + C + D + 8, then the value of A + B + C + D is**

8 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

A + 4 = B + 5 = C + 6 = D + 7 = P + B + C + D + 8

A + 4 = B + 5 A – 1 = B

A + 4 = C + 6 A – 2 = C

A + 4 = D + 7 A – 3 = D

Now, A + 4 = A + A – 1 + A – 2 + A – 3 + 8

A $= \frac{2}{3}$

$B = \frac{- 1}{3}, C = \frac{- 4}{3}, D = \frac{- 7}{3}$

So, A + B + C + D =

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New answer posted•a year ago

Quantitative Aptitude Prep Tips for MBA Class 12th

Akshat’s age is double that of Gaurav. The sum of the ages of Akshat and Gaurav is double that of Rishab. 6 years hence the sum of the ages of Akshat and Rishab will be three times the age of Gaurav. Find their present ages.

5 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

Let the ages of Akshat, Rishab, Gaurav be X, Y, Z years respectively.

X = 2 Z &

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Quantitative Aptitude Prep Tips for MBA

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