Quantitative Aptitude Prep Tips for MBA

LCM of 70, 84, 280 is 840.

Let total work = 840 units.

Per hour work of P = $\frac{840}{70}=12\text{?}units/hour$ $$

Per hour work of Q = $\frac{840}{84}=10\text{?}units/hour$ $$

Per hour work of R = $\frac{840}{280}=3\text{?}units/hour$ $$

Number of hours they require together =

$\frac{}{}$ $\frac{840}{12+10+3}=\frac{840}{25}$  = 33 hours and 36 minutes

Five years ago the ratio of their ages was 5:3 with the total age being 64 years. Their individual ages will be 40 and 24 years.

Today their ages will be 45 years and 29 years and after 9 years their ages will be 54 and 38 years.

Required ratio will be 27 : 19.

612 = 212 * 312. For perfect cubes, power must be multiple of 3.

Therefore, power of 2 equal 20, 23, 26, 29, 212 and power of 3 equals 30, 33, 36, 39, 312 So, number of divisors equal 5* 5 = 25.

New rent = 2730 per month.  Rs. 2720 * 12 = Rs. 32640 per year

Net for X = 70 * 4 + 50 * 3 + 66 * 5 = 760

For Y = 50 * 4 + 70 * 8 = 760

For Z = 40 * 7 + 24 * 5 = 400

The shares will 12920, 12920 and 6800.

When T2 is at 45 points, T3 is at 40 points, that is, T2 can beat T3 by 5 points in a 45 point game. In a 765 point game, T2 can beat T3 by $\frac{765}{45}*5$ $\frac{}{}$ = 85 points.

Selling price = Rs. 16.56

Cost price for 38/% profit = 1.38 C.P. = 16.56

C.P. = $\frac{15}{1.25}$ $\frac{}{}$ = Rs. 12

$\begin{array}{l}\frac{Chemical one }{Chemical second}=\frac{\left(13.5-12\right)}{\left(12-9\right)}\\ =\frac{1.5}{3}=\frac{1}{2}\end{array}$

Let the price of P2 per kg be Rs. X. Then the price of P1 per kg = Rs. 3X.

1 kg of P3 P3contains

$\left(\frac{2}{7}\right)*1,i.e.,\frac{2}{7}kgofAand\frac{5}{7}kgofB$

Price of 1 kg of P3 = $\left(\frac{2}{7}\right)*3X+\left(\frac{5}{7}\right)X=\left(\frac{11}{7}\right)X$ $\frac{}{}\frac{}{}\frac{}{}$

P2y the given condition,

$\begin{array}{l}\frac{11X}{7}=10.4-1.6=Rs.8.8\\ \Rightarrow X=8.8*\left(\frac{7}{11}\right)=5.6\end{array}$

Hence, the price of P1 per kg = 3X = 3 * 5.6 = Rs. 16.8

Price of P2 per KG = Rs5.6

Let X = working time

$\frac{74}{100}*5574300$

Solve to get X = 6 hours.