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Quantitative Aptitude Prep Tips for MBA

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Quantitative Aptitude Prep Tips for MBA Class 12th

A cylindrical container has its height twice the radius of the base. If due to imperfection in measuring callipers, 1 cm is taken as 1.02 cm, the percentage error in the volume is

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Payal Gupta

Contributor-Level 10

Let h = height of the container,

Given, h = 2r

$∴$ Volume v = πr²h = πr² (2r) = 2πr³

$∴$ Absolute error = (1.02)³ * 2πr³ − 2πr³ * 13

= 2πr³ [ (1.02)² − 1] = 2πr³ [1.0612 − 1]

= 0.0612 * 2πr³

$∴$ % error $= \frac{0.0612 * 2 π r^{3}}{2 π r^{3}} * 100 % = 6.12 %$

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Quantitative Aptitude Prep Tips for MBA Class 12th

If $\sqrt[]{a^{b}} = 5 b + a^{2}$ then (a, b) could be

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Payal Gupta

Contributor-Level 10

Put a = 2, b = 12 in $\sqrt[]{a^{b}} = 5 b + a^{2}$

$∴ \sqrt[]{2^{12}} = 5 * 12 + 4 = 64$

$\Rightarrow$ 26 = 64, which is true.

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Quantitative Aptitude Prep Tips for MBA Class 12th

P1 was a very lazy person. When he went for hunting a job, everyone refused to engage him, except farmer P2. P2 engaged P1 at a wage of Rs. 300 per day for a month of 28 days. However, he set a condition that P1 would forfeit Rs. 100 each day if he idled. P1 accepted the job. At the end of the month, it was found that neither owed the other anything. How many days did P1 work in that month?

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Payal Gupta

Contributor-Level 10

For every day's work, P1 can afford to miss 3 days.

Hence, to break even it has to be 7 days' work in 28 days.

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Quantitative Aptitude Prep Tips for MBA Class 12th

If a bus increase its usual speed by 7 km/hr, then it can travel distance AB in one hour less then the usual time. If the bus decreases its usual speed by 5 km/hr, then it can travel distance AB in 2 hours more than the usual time. What is the distance AB?

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Payal Gupta

Contributor-Level 10

Let Ab = X km and speed of bus be Y km/hr and time be T hrs original equation becomes $\frac{X}{Y} = T . . . . . (1)$

By increasing speed by 7 km/hr equation becomes

$\frac{X}{y + 7} = T - 1 . . . . . (2)$

By decreasing speed by 5 km/hr equation becomes

$\frac{X}{y - 5} = T + 2 . . . . . (3)$

On solving equation 1, 2 & 3 we get the value of y as and

$\frac{35}{3}$ and $T = \frac{8}{3}$

$∴$ AB = X = $\frac{280}{9}$

≈ 31 km

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Quantitative Aptitude Prep Tips for MBA Class 12th

Given A + 4 = B + 5 = C + 6 = D + 7 = A + B + C + D + 8, then the value of A + B + C + D is

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Payal Gupta

Contributor-Level 10

A + 4 = B + 5 = C + 6 = D + 7 = P + B + C + D + 8

A + 4 = B + 5 A – 1 = B

A + 4 = C + 6 A – 2 = C

A + 4 = D + 7 A – 3 = D

Now, A + 4 = A + A – 1 + A – 2 + A – 3 + 8

A $= \frac{2}{3}$

$B = \frac{- 1}{3}, C = \frac{- 4}{3}, D = \frac{- 7}{3}$

So, A + B + C + D =

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Quantitative Aptitude Prep Tips for MBA Class 12th

AB is a railway line 220 km long, and three trains P, Q, R, travel on it at the speeds of 25 km/hr, 20 km/hr and 30 km/hr respectively. P and Q leaves A at 7 a.m. and 8: 15 a.m. respectively, and R leaves B at 10.30 a.m. Where will P be equidistant from Q and R?

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Payal Gupta

Contributor-Level 10

Suppose P is midway between Q & R. Now, X hours after 7 a.m.

25 X – 20 (X – 1.25) = 220 – 25X – 30 (X – 3.5) etc.

So, 12 o'clock & 125 km from A.

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Quantitative Aptitude Prep Tips for MBA Class 12th

Akshat's age is double that of Gaurav. The sum of the ages of Akshat and Gaurav is double that of Rishab. 6 years hence the sum of the ages of Akshat and Rishab will be three times the age of Gaurav. Find their present ages.

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Payal Gupta

Contributor-Level 10

Let the ages of Akshat, Rishab, Gaurav be X, Y, Z years respectively.

X = 2 Z . (1)

X + Z = 2 Y . (2)

(X + 6 + Y + 6) = 3 (Z + 6) &nb

...more

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Quantitative Aptitude Prep Tips for MBA Class 12th

In Rajdhani Express, there are 10 boggies which carries on an average of 20 passengers per boggie. If atleast 12 passengers were sitting in each boggie and no boggie has equal number of passenger then maximum, how many passenger can be accommodated in a boggie?

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Payal Gupta

Contributor-Level 10

Total number of passenger is the Rajdhani Express = 10 * 20 = 200

So, in the 9 boggies the minimum number of total passengers = 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 144

Hence, the minimum number of passenger in one boggie can be (200? 144) = 56

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Quantitative Aptitude Prep Tips for MBA Class 12th

A, B and C can alone do a work in 15 days, 20 days and 30 days, respectively. They work together for some time after which C leaves. A total of Rs. 18000 is paid for the work and B gets Rs. 6000 more than C. For how many days did A work?

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Payal Gupta

Contributor-Level 10

Let A and B work for m days and C for n days to complete the work. Therefore,

$\frac{m}{15} + \frac{m}{20} + \frac{n}{30} = 1$ . (1)

Out of the total of Rs. 18000, B gets Rs. 6000 more than C.

i.e., $\frac{m}{20} - \frac{n}{30} = \frac{6000}{18000} = \frac{1}{3}$ . (2)

On adding Eqs. (1) and (2), we get

$\frac{m}{15} + \frac{2 m}{20} = \frac{4}{5} \Rightarrow m = 8$

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Quantitative Aptitude Prep Tips for MBA Class 12th

A quadratic function f(x) attains a maximum of 3 at x = 1. The value of the function at x = 0 is 1. What is the value of f(x) at x = 10?

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Payal Gupta

Contributor-Level 10

Let f (x) = px²+ qx + k, where p, q and k are integers, and p ≠ 0

$∴$ f (0) = k = 1

$∴$ f (x) = px² + qx + 1

= px² +qx + k (Differentiate both sides with respect to x)

$∴$ f' (x) = 2px + q

For maxima or minima f' (x) = 0, x = $- \frac{q}{2 p}$

f (x) attains maximum at x = 1

$∴$ q = − 2p

f (1) = p + q + 1 = 3

$∴$ 1 − p = 3

$∴$ p = − 2

$∴$ q = 4

$∴$ f (x) = −2x² + 4x + 1

f (10) = − 200 + 40 + 1 = −159

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