Quantitative Aptitude Prep Tips for MBA
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New answer posted
a month agoContributor-Level 10
Let A = abc and B = cba
Therefore, B – A = 100c + 10b + a – (100a + 10b + c) = 99 (c – a). B – A is a multiple of 7.
Therefore, c – a = 7 (a, c) (1, 8) or (2, 9).
Hence, number is between 108 to 198 or 209 to 299.
New answer posted
a month agoContributor-Level 10
Suppose the hound catches the rabbit in t minutes
Number of jumps by the rabbit = 35t & distance covered = 20 * 35t = 700 t cm.
Similarly Distance covered by hound = 25t * 60 = 1500t cm.
Now, 1500 t – 700t = 7000 cm or t = min.
New answer posted
a month agoContributor-Level 10
When S1 runs 1900 metres, S3 would run 1862 metres. Hence, the start given is 38/1900 * 2000 = 40 metres
New answer posted
a month agoContributor-Level 9
In this problem, we are looking for the LCM of the divisors, that is, 3 and 4 or any of their multiple to which the desired remainder 2 can be added. The smallest such number is 2. The others will be 14, 26, 38, 50, 62, 74, 86 and 98, that is there are 9 such numbers
New answer posted
a month agoContributor-Level 9
The new time is of the old time. If time becomes , then new speed should have been of the initial speed. Therefore
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