Quantitative Aptitude Prep Tips for MBA

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New answer posted•a year ago
S
a year ago

Let the speed of A be x km/hr and speed of B be y km/hr, then:

55x=55y−12           .....   (1)

Also,  55x=51y−110           .....   (2)

On solving both equation (1) & (2) we get x = 11 km/hr and y = 10 km/hr.

...Read more

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Total S.P. will be

8× [2.36x]+16100 [x4+1]120=18.88x+4.8x +19.2

= [x8]216=27x

Profit = 23.68x + 19.2 − 27x = 19.2 - 3.32x

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

( A B )     ×     ( B C )     ×     ( C D )     =     A D

⇒           5 6     ×     1 3 1 4     ×     9 4     =     1 9 5 1 1 2    

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New answer posted•a year ago
S
a year ago

The new time is 1 3  of the old time. If time becomes 1 3 , then new speed should have been   3 1 of the initial speed. Therefore

3 S     −     S S     ×     1 0 0     =     2 0 0 %

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New question posted•a year ago
New answer posted•a year ago
S
a year ago

Using the successive percentage change rule, we have

− 2 5 + x − 2 5 x 1 0 0 = 2 0

3 x 4 = 4 5

x =60%

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