Sequence and Series

4. Here, $a_n=\frac{2n-3}{6}$

Putting n=1,2,3,4,5 we get,

$a_1=\frac{2*1-3}{6}=\frac{2-3}{6}=-\frac{1}{6}$

$a_2=\frac{2*2-3}{6}=\frac{4-3}{6}=\frac{1}{6}$

$a_3=\frac{2*3-3}{6}=\frac{6-3}{6}=\frac{3}{6}=\frac{1}{2}$

$a_4=\frac{2*4-3}{6}=\frac{8-3}{6}=\frac{5}{6}$

$a_5=\frac{2*5-3}{6}=\frac{7}{6}$

Hence, the first five terms are $-\frac{1}{6},\frac{1}{6},\frac{1}{2},\frac{5}{6},and\frac{7}{6}$

1. Here a_n = n (n + 2)

Substituting n=1,2,3,4,5 we get,

a₁=1 (1+2)=1 * 3=3

a₂=2 (2+2)=2 * 4=8

a₃=3 (3+2)=3 * 5=15

a₄=4 (4+2)=4 * 6=24

a₅=5 (5+2)=5 * 7=35.

Hence, the first five terms are 3,8,15,24 and 35

Yes,  NCERT Solutions for Class 11 Maths Chapter 8 Sequences and Series are readily available in PDF format. These NCERT Solution PDF for Sequence and Series are designed for students to get enough practice problems to solve and offline access of the resource to practice whenevre they want.

Shiksha provides well-organized, chapter-wise solutions in downloadable PDF format for all exercise. These solutions cover all the NCERT textbook exercises including 8.1, 8.2, and 8.3 with step-by-step explanations, important formulas, and solved examples.

The Sequences and Series in Class 11 Maths typically carries a weightage of 6 to 8 marks out of the total 80 marks in the theory paper of mathematics. Various type of questions are asked from this chapter including MCQs, Very short answer, short and long answer type questions.  Students can use NCERT Solutions for Sequence and Series for better preparation of the exams.