The p -Block Elements
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New answer posted
4 months agoContributor-Level 10
In BF3, boron is sp2 hybridized.
? shape of BF3 = planar.
In [BH4]–, boron is sp3 hybridized, thus the shape is tetrahedral.

New answer posted
4 months agoContributor-Level 10
On heating boric acid above 370 K, it forms metaboric acid, HBO2 which on further heating yields boric oxide B2O3.
H3B2O3 → HBO2 → B2O3
New answer posted
4 months agoContributor-Level 10
Boric acid is a Lewis acid since it accepts electrons from hydroxyl ion of H2O molecule. It is not a protic acid.
B (OH)3 + 2HOH → [B (OH)4]– + H3O+
New answer posted
4 months agoContributor-Level 10
In BCl3, there is only six electrons in the valence shell of B atom. Thus, the octet is incomplete and it can accept a pair of electrons from water and hence BCl3 undergoes hydrolysis. Whereas, in CCl4, C atom has 8 electrons and its octet is complete. That's why it has no tendency to react with water.
New answer posted
4 months agoContributor-Level 10
In BF3, central atom has only six electrons after sharing with the electrons of the F
atoms. It is an electron-deficient compound and thus behaves as a Lewis acid.
New answer posted
4 months agoContributor-Level 10
BCl3 is quite stable. Because there is absence of d- and f-electrons in boron three valence electrons (2s2 2px1) are there for bonding with chlorine atom. In Tl the valence s-electron (6s2) are experiencing maximum inert pair effect. Thus, only 6p1 electron is available for bonding. Therefore, BCl3 is stable but TlCl3 is comparatively unstable.
New answer posted
4 months agoContributor-Level 10
(i) B to Tl
Common oxidation states are +1 and +3. The stability of +3 oxidation state decreases from B to Tl while +1 oxidation state increases from B to Tl.
(ii) C to Pb
The common oxidation states are +4 and +2. Stability of +4 oxidation state decreases from C to Pb.
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