The p -Block Elements

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V
Vishal Baghel

Contributor-Level 10

In diborane the boron atoms are sp³ hybridized.

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V
Vishal Baghel

Contributor-Level 10

The boiling point order is: H? S < H? Se < H? Te < H? O

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V
Vishal Baghel

Contributor-Level 10

Carbon atoms in diamond are sp³ hybridized and those in graphite are sp² hybridized.

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R
Raj Pandey

Contributor-Level 9

Bismuth (Bi) is a metal in group 15. Its hydride is BiH? , which is the strongest reducing agent due to its the lowest thermal stability.

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R
Raj Pandey

Contributor-Level 9

Oxidation States (O.S) of Phosphorus (P):

  • Hypophosphorous acid – H? PO? : +1
  • Orthophosphoric acid – H? PO? : +5
  • Hypophosphoric acid – H? P? O? : +4
  • Orthophosphorous acid – H? PO? : +3

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R
Raj Pandey

Contributor-Level 9

(a) Haber's process is used for the synthesis of NH?
(b) Ostwald's process is used to synthesize HNO?
(c) Contact process is used for the synthesis of H? SO?
(d) Hall-Héroult process is used for the extraction of aluminium.

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a month ago

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A
alok kumar singh

Contributor-Level 10

Iron (III) iodide (FeI? ) does not exist because it is unstable. The Fe³? ion is a strong enough oxidizing agent to be easily reduced to Fe²? by the I? ion, which in turn is oxidized.

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R
Raj Pandey

Contributor-Level 9

Oxidation state of N
| NO | +2 |
|-|-|
| NO? | +4 |
| N? O | +1 |
| NO? | +5 |
So, order of oxidation state is
NO? > NO? > NO > N? O

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a month ago

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A
alok kumar singh

Contributor-Level 10

Na? SO? + H? SO? → SO? + Na? SO? + H? O
SO? + 2NaOH → Na? SO? + H? O
Na? SO? + SO? + H? O → 2NaHSO?

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a month ago

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