Units and Measurement
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A vernier caliper has 10 main scale divisions coinciding with 11 vernier scale divisions. 1 main scale division equals 5 mm. The least count of the device is
A vernier caliper has 10 main scale divisions coinciding with 11 vernier scale divisions. 1 main scale division equals 5 mm. The least count of the device is
10 M = 11 V
Þ 1V =
Þ LC = |M – V|
=
If force (F), mass (M), length (L) are taken as fundamental quantities, dimensions of time will be
If force (F), mass (M), length (L) are taken as fundamental quantities, dimensions of time will be
F = Ma = ML T2
-> T2 = ML/F
F
In which of the following numerical values, all zeroes are significant?
In which of the following numerical values, all zeroes are significant?
In a number without decimal, trailing zeros are insignificant. If a number has a decimal, then preceding zeros are insignificant.
Hence, in 40.40 all zeros are significant
Match the following.
(a)
Temperature
(p)
Light Year
(b)
Mass
(q)
Shake
(c)
Length
(r)
Fahrenheit
(d)
Time
(s)
Atomic mass unit
Match the following.
|
(a) |
Temperature |
(p) |
Light Year |
|
(b) |
Mass |
(q) |
Shake |
|
(c) |
Length |
(r) |
Fahrenheit |
|
(d) |
Time |
(s) |
Atomic mass unit |
Unit of temperature is Fahrenheit
Unit of mass is atomic mass of unit
Unit of length is light year
Unit of time is shake
In a measurement, a choice change of different units
In a measurement, a choice change of different units
In a measurement, a choice of change of different units does not change the number of significant figures.
In which of the following numerical values, all zeroes are significant?
In which of the following numerical values, all zeroes are significant?
In a number without decimal, trailing zeros are insignificant. If a number has a decimal, then preceding zeros are insignificant.
Hence, in 40.40 all zeros are significant
If force (F), mass (M), length (L) are taken as fundamental quantities, dimensions of time will be
If force (F), mass (M), length (L) are taken as fundamental quantities, dimensions of time will be
Two rods with lengths 20.123 cm and 18.1 cm are placed side by side. The difference in their lengths is
Two rods with lengths 20.123 cm and 18.1 cm are placed side by side. The difference in their lengths is
(b) L1= Length of rod =20.123cm
L2= Length of rod = 18.1cm
Difference in length 
= 20.123-18.1
=2.0 cm
The pitch of the screw gauge is 1mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while 72nd division on circular scale coincides with the reference line, The radius of the wire is:
The pitch of the screw gauge is 1mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while 72nd division on circular scale coincides with the reference line, The radius of the wire is:
Zero error = +0.08 mm.
Diameter = 1 + 72 * 0.01 – 0.08 = 1.64 mm
Radius = 0.82 mm
The period of oscillation of a simple pendulum is Measured value of ‘L’ is 1.0m from meter scale having a minimum division of 1mm and time of one-complete oscillation is 1.95s measured from stopwatch of 0.01s resolution. The percentage error in the determination of ‘g’ will be:
The period of oscillation of a simple pendulum is Measured value of ‘L’ is 1.0m from meter scale having a minimum division of 1mm and time of one-complete oscillation is 1.95s measured from stopwatch of 0.01s resolution. The percentage error in the determination of ‘g’ will be:
