Tags Units and Measurement

Units and Measurement

Get insights from 125 questions on Units and Measurement, answered by students, alumni, and experts. You may also ask and answer any question you like about Units and Measurement

Follow Ask Question

125

Questions

Discussions

Active Users

Followers

New answer posted

a month ago

Units and Measurement Class 11th

A vernier caliper has 10 main scale divisions coinciding with 11 vernier scale divisions. 1 main scale division equals 5 mm. The least count of the device is

0 Follower 1 View

alok kumar singh

Contributor-Level 10

10 M = 11 V

Þ 1V = $\frac{10}{11}$ * 5 mm

Þ LC = |M – V|

= $\frac{5}{11}$ mm

0 0

New answer posted

a month ago

Units and Measurement Class 11th

If force (F), mass (M), length (L) are taken as fundamental quantities, dimensions of time will be

0 Follower 1 View

alok kumar singh

Contributor-Level 10

F = Ma = ML T²

-> T² = ML/F

0 0

New answer posted

a month ago

Units and Measurement Class 11th

In which of the following numerical values, all zeroes are significant?

0 Follower 1 View

alok kumar singh

Contributor-Level 10

In a number without decimal, trailing zeros are insignificant. If a number has a decimal, then preceding zeros are insignificant.

Hence, in 40.40 all zeros are significant

0 0

New answer posted

a month ago

Units and Measurement Class 11th

Match the following.

(a)	Temperature	(p)	Light Year
(b)	Mass	(q)	Shake
(c)	Length	(r)	Fahrenheit
(d)	Time	(s)	Atomic mass unit

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

Unit of temperature is Fahrenheit

Unit of mass is atomic mass of unit

Unit of length is light year

Unit of time is shake

0 0

New answer posted

a month ago

Units and Measurement Class 11th

In a measurement, a choice change of different units

0 Follower 1 View

alok kumar singh

Contributor-Level 10

In a measurement, a choice of change of different units does not change the number of significant figures.

0 0

New answer posted

2 months ago

Units and Measurement Class 11th

In which of the following numerical values, all zeroes are significant?

0 Follower 1 View

alok kumar singh

Contributor-Level 10

In a number without decimal, trailing zeros are insignificant. If a number has a decimal, then preceding zeros are insignificant.

Hence, in 40.40 all zeros are significant

0 0

New answer posted

2 months ago

Units and Measurement Class 11th

If force (F), mass (M), length (L) are taken as fundamental quantities, dimensions of time will be

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$F = m a = \frac{M L}{T^{2}}$

$\Rightarrow T^{2} = \frac{M L}{F}$

$\Rightarrow [T] = ⌊ M^{1 / 2} L^{1 / 2} F^{- 1 / 2} ⌋$

0 0

New answer posted

2 months ago

Units and Measurement Class 11th

Two rods with lengths 20.123 cm and 18.1 cm are placed side by side. The difference in their lengths is

0 Follower 1 View

Raj Pandey

Contributor-Level 9

(b) L₁₌ Length of rod =20.123cm

L₂₌ Length of rod = 18.1cm

Difference in length

= 20.123-18.1

=2.0 cm

0 0

New answer posted

2 months ago

Units and Measurement Class 11th

The pitch of the screw gauge is 1mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while 72^nd division on circular scale coincides with the reference line, The radius of the wire is:

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$L C = \frac{1}{100} m m = 0.01 m m$

Zero error = +0.08 mm.

Diameter = 1 + 72 * 0.01 – 0.08 = 1.64 mm

Radius = 0.82 mm

0 0

New answer posted

2 months ago

Units and Measurement Class 11th

The period of oscillation of a simple pendulum is $T = 2 π \sqrt[]{\frac{L}{g}} .$ Measured value of 'L' is 1.0m from meter scale having a minimum division of 1mm and time of one-complete oscillation is 1.95s measured from stopwatch of 0.01s resolution. The percentage error in the determination of 'g' will be:

0 Follower 4 Views

Vishal Baghel

Contributor-Level 10

$T = 2 π \sqrt[]{\frac{L}{g}} o r T^{2} = 4 π^{2} (\frac{L}{g})$

$\Rightarrow g = 4 π^{2} (\frac{L}{T^{2}})$

$\Rightarrow \frac{Δ g}{g} % = (\frac{Δ L}{L} + \frac{2 Δ T}{T}) % = [\frac{1 m m}{1 m} + \frac{2 * 0.01}{1.95}] * 100 % = (0.001 + 0.0102) * 100 = 1.13 %$

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
679k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Units and Measurement

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience