Vellore

Hi Sachin,
If you want computer science branch in VIT,Vellore in category 1, your rank must be less than 5000. You may get CSE branch at a rank range of 10 -15k but in category 5 where tuition fee is around 4.88 lakhs excluding hostels.

Well, frankly speaking, this is really tough to predict VITEEE score vs rank and if any one does, its going to be hypothetical. But, if you want to take mechanical engineering there in category 1, then your rank must be around 15000.

If your rank is under 20k and if you got category 1 then the total fees is around 11.5 lakhs. The fees depends on the branch you choose.

There is no marks vs rank ratio as they don't reveal your marks. However, if you talk about rank then under 15k, it is good.

Hello Abhishek,
VIT, Vellore is one of the most prestigious private college of India. Top class faculties and top class education with quality students is provided to its students. Many companies go for placements at Vellore with different scale of pay. The highest package offered in VIT this year was 16 LPA by LinkedIn. Many other companies like Flipkart, EBay, Deshaw, Cisco, InMobi and McKinsey offered package of more than 10 lacs and average salary is just about 3-4 LPA.
For more details, you can visit this link:
http://www.vit.ac.in/placement

You can contact the institute for the same. They may take more fee for the same. Otherwise, I don't think there is any other option.

VIT, Vellore is good in terms of placement but not so good for IT branch.

Both are good at their places but for IT branch RV College is the best choice.

In which course would you want to know?

Hello,
All the colleges you mentioned above have their own entrance examinations for admission into engineering courses. SRM conducts SRMJEEE entrance examination, BITS, Pilani conducts BITSAT entrance examination, VIT conducts VITEEE entrance examination. Kindly check on the official website of the respective colleges for applying online. I hope this answers your question. If you have any further questions, kindly revert.