Amines

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New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

4 months ago

0 Follower 16 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

4 months ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

Diazonium salts of aromatic amines are more stable

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

p- toluenesulphonyl chloride

Only gives soluble product with alkali for 1° amine and for 2°- amine it gives insoluble product.

 

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

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V
Vishal Baghel

Contributor-Level 10

Allylic halide have halogen bonded to sp³ carbon which is adjacent to > C = C <

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V
Vishal Baghel

Contributor-Level 10

(a) List-I List-II
CO, HCl Anhydrous AlCl? /CuCl → (ii) Gattermann-Koch reaction
(b) R – C=O .
(c) R – CH? OH + R'COOH - (conc. H? SO? )-> (iv) Esterification
(d) R – CH? COOH - ( (i) X? /RedP (ii) H? O )-> (i) Hell-Volhard Zelinsky reaction

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

In the presence of peroxide, addition of HBr to unsymmetrical alkenes take place by anti-Markovnikov's rule/Peroxide effect/Kharash effect.

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4 months ago

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V
Vishal Baghel

Contributor-Level 10

kc = [O? ]² / [O? ]³
3 * 10? = [O? ]² / [4 * 10? ²]³
[O? ]² = 192 * 10? ⇒ [O? ] = 4.38 * 10? ³²

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

Kjeldahl's method does not work for heterocyclic and azo compounds.

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