Amines

Intermolecular H- bonding and intra-molecular H- bonding producing compound may be the phenol derivatives.

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Ans: N, N-dimethylbenzenanmine 

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Ans:

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Ans:  CH₃CH₂CH₃ < CH₃CH₂NH₂ < CH₃CH₂OH

As oxygen is more electronegative than nitrogen therefore, the O-H bond is more polar than the N-H bond. So ethanol has more dipole moments than ethylamine. Propane is non- polar in nature hence, had the least among all. 

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Ans: CS₂ is a non-polar solvent which decreases the activating effect of? NH₂. As a result, mono substitution occurs only at o- and p- positions giving a mixture of 2-bromoaniline (minor) and 4-bromoaniline (major) as products. 

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Ans: The azo products have an extended conjugate system with both aromatic rings linked by the –N=N- bond. These compounds are frequently colored and used as dyes. Benzene diazonium chloride reacts with phenol to form p-hydroxy azobenzene by coupling the phenol molecule in its para position with the diazonium salt. This is referred to as a coupling reaction.

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Ans: Amides are the byproducts of the acylation reaction. The reaction is carried out in the presence of a stronger base than the amine, such as pyridine, which removes the formed HCl and shifts the equilibrium to the right.

This is a Short Type Questions as classified in NCERT Exemplar

Ans: As the electronegativity of oxygen is more than the electronegativity of a nitrogen atom, the O−H bond is more polar than the N−H bond, therefore MeOH is stronger acid than MeNH₂ or MeNH₂ is stronger base than MeOH.